Using a passed by reference struct variable in C

Question

I have a basic pointer question. I have some code like this: Please let me know if anything is wrong in the following code:

struct abc {
  int a;
  int b;
};

void func2(int*); // defined elsewhere

void func1 (struct abc *p1)
{
  struct abc var1 = *p1; // ======> Can I do this ? 

  func2(&var1.b);
  func2(&p1->b);      // =========> Which of these 2 is right ? 
}

what is the signature of func2()?

Eugene S
– Eugene S

2011-08-23 17:32:06 +00:00
Commented Aug 23, 2011 at 17:32 — Eugene S
– Eugene S, Commented Aug 23, 2011 at 17:32
func2(int *) is the signature.

Vin
– Vin

2011-08-23 17:36:23 +00:00
Commented Aug 23, 2011 at 17:36 — Vin
– Vin, Commented Aug 23, 2011 at 17:36

Arnaud Le Blanc · Accepted Answer · 2011-08-23 17:32:22Z

10

struct abc var1 = *p1; ======> Can I do this ?

Yes, this copies the struct pointed by p1 in the local variable var1.

func2(&var1.b); func2(&p1->b); =========> Which of these 2 is right ?

Both, if func2() accepts a int* as parameter. It depends if you want func2 to modify p1->b or var1.b.

answered Aug 23, 2011 at 17:32

Arnaud Le Blanc

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