How to pass arguments to shell script from a scala application?

Question

I have a Scala application which needs to call the shell script by passing some arguments to it.

I followed the below answer and I am able to call the shell script from scala app without passing any arguments. But I have no idea how to pass the arguments.

Execute shell script from scala application

object ScalaShell {

  def main(args : Array[String]): Unit = {
    val output = Try("//Users//xxxxx//Scala-workbench//src//main//scala//HelloWorld.sh".!!) match {
      case Success(value) =>
        value
      case Failure(exception) =>
        s"Failed to run: " + exception.getMessage
    }
    print(output)
  }

}

HelloWorld.sh

#!/bin/sh
# This is a comment!
echo Hello World

Current Output:

Hello World

Expected Output:

Hello World, arg1 arg2 (where arg1 and arg2 were passed from scala)

Goosefand · Accepted Answer · 2022-04-01 14:25:29Z

3

It is explained in great detail in Scala docs but my favorite way is this:

List("echo", "-e", "This \nis \na \ntest").!!

simply call the !! method on a list where the first element is the script/command and the remaining elements are the args/options.

answered Apr 1, 2022 at 14:25

Goosefand

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Comments

Jeberdson Abraham · Accepted Answer · 2022-04-04 07:19:20Z

1

In addition to @goosefand's answer, I have also added how to receive the arguments which is passed from scala in the shell script.

Scala:

object ScalaShell {

  def main(args : Array[String]): Unit = {
    val output = Try(Seq("//Users//xxxxx//Scala-workbench//src//main//scala//HelloWorld.sh", "arg1","arg2").!!) match {
      case Success(value) =>
        value
      case Failure(exception) =>
        s"Failed to run: " + exception.getMessage
    }
    print(output)
  }

}

Shell Script:

#!/bin/sh
echo Processing files $1 $2

Output:

Hello world arg1 arg2

answered Apr 4, 2022 at 7:19

Jeberdson Abraham

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