ggplot2 Plotting scatterplot with 2 variables and labelling x-axis based on another variable

Question

I have the following dataframe:

df<-data.frame(ID = c(1,2,3,4,5,6,7,8,9,10),
         group = c(1,1,1,1,1,2,2,2,3,3),
         level = c(0.1,0.5,0.2,0.3,0.6,0.7,0.8,0.5,0.9,0.3))

I would like to use ggplot2 to plot a scatter plot, where every point (x,y) corresponds to the values of (ID,level). But I want to label the x-axis based on the group value, so that the x-axis in this case would have 3 ticks: under tick "1", there would be 5 points, tick "2" with 3 points and tick "3" with 2 points.

Could you please add the current and expected output and what has already failed? — NelsonGon
– NelsonGon, Commented Apr 1, 2022 at 19:22
From your description e.g "under tick "1", there would be 5 points" it sounds that your result could be achieved by simply mapping group directly on x. Maybe you could clarify how your plot should look like. — stefan
– stefan, Commented Apr 1, 2022 at 19:24
Sorry what I meant was I want the plot to look like three different scatterplots (stitched together), one based on each group value and the points based on (ID, level) values, so for example under tick "1", the points that are plotted should be: (1, 0.1), (2, 0.5), (3, 0.2), (4, 0.3), (5, 0.6). — user1490
– user1490, Commented Apr 1, 2022 at 19:46

stefan · Accepted Answer · 2022-04-01 20:06:02Z

1

Similar idea as by Allan but with some additional tweaking to show the group labels as tick labels:

library(ggplot2)

breaks <- tapply(df$ID, df$group, median)
ggplot(df, aes(ID, level)) +
  geom_point() +
  scale_x_continuous(breaks = breaks, labels = NULL) +
  facet_grid(~group, scales = "free_x", switch = "x" , space = "free_x") +
  theme(strip.placement = "outside",
        strip.background.x = element_blank())

answered Apr 1, 2022 at 20:06

stefan

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Allan Cameron · Accepted Answer · 2022-04-01 20:08:42Z

1

Are you looking for facets?

ggplot(df, aes(ID, level)) + 
  geom_point() + 
  facet_grid(.~group, scales = "free_x", space = "free_x") +
  scale_x_continuous(breaks = 1:10, expand = expansion(0, 0.5)) +
  theme(panel.spacing = unit(0, "mm"),
        text = element_text(size = 16),
        strip.background = element_rect(fill = "#A0B6FF", color = "black"),
        panel.border = element_rect(colour = "grey", fill = NA),
        strip.text = element_text(size = 20))

edited Apr 1, 2022 at 20:08

answered Apr 1, 2022 at 19:58

Allan Cameron

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1 Comment

stefan Over a year ago

This time your faster than. Spend to much time on tweaking the plot. ;)

Angel F. Escalante · Accepted Answer · 2022-04-01 19:37:15Z

0

The tidyverse way:

library(tidyverse)
df %>% ggplot(aes(x = group, y = level)) + 
  geom_point(aes(color = as.factor(ID)), size = 2) +
  scale_x_continuous(breaks = seq(1:3))

answered Apr 1, 2022 at 19:37

Angel F. Escalante

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