How to sum an array of objects with a condition in typescript

Question

Hi I am doing addition of key value from objects of an array. I want to exclude the object from the addition if it has some conditions. Example:

var arrItem = [{"id": 1, "value":100},{"id": 2, "value":300},{"id": 3, "value":400}];

//addition
this.sum = arrItem.map((a:any) => a.value).reduce(function (a:any, b:any) {
          return a + b;
        });

console.log(this.sum) // ====>>> getting 800

I want to exclude object with id==2 from summation. How I can filter this out so that I will get result as ==> 500

@TobiasS. I am not getting exactly how to use filter() here. — Optimist Rohit
– Optimist Rohit, Commented Apr 12, 2022 at 6:41

mgm793 · Accepted Answer · 2022-04-12 06:41:16Z

6

You can do it with reduce:

this.sum = arrItem.reduce((acc, val) => {
  if (val.id !== 2) return acc + val.value;
  return acc;
}, 0);

answered Apr 12, 2022 at 6:41

mgm793

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2 Comments

Optimist Rohit Over a year ago

I am getting NAN

mgm793 Over a year ago

@OptimistRohit codesandbox.io/s/wandering-leaf-i93t9p?file=/src/index.js

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