How do I get href attribute value from the given HTML using Python+Selenium?

Question

I have HTML as shown (modified to make it brief)

ht=<a class="title" href="http:/www.myref.com/1235" title="This is link to my ref">This is my ref</a>

Now from here, I want to extract the "http:/www.myref.com/1235"

ht.get_text()

gives me only the text part This is my ref.

ht.getAttribute('href') geeksforgeeks.org/get_attribute-element-method-selenium-python — Tim Roberts
– Tim Roberts, Commented Apr 17, 2022 at 4:35
@TimRoberts thanks, I get TypeError: 'NoneType' object is not callable in my try. — stochastic learner
– stochastic learner, Commented Apr 17, 2022 at 4:45
Please add more detail like code snippet and error stacktrace — NarendraR
– NarendraR, Commented Apr 17, 2022 at 5:03

cruisepandey · Accepted Answer · 2022-04-17 05:19:51Z

1

If ht is a webelement then,

ht.get_attribute('href')

should give you http:/www.myref.com/1235

Since you are getting TypeError: 'NoneType' object is not callable

This could mean either

Put some delay before ht and try again with ht.get_attribute('href')

answered Apr 17, 2022 at 5:19

cruisepandey

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