javascript split array in two arrays

Question

I am trying to split this array into two different arrays using the values inside the first array.

This is my initial array:

    "carList": [
      {
        "brand": [
          {
            "model": [
              { "motor": { "id": 1 }, "color": 10 },
              { "motor": { "id": 2 }, "color": 20 },
              { "motor": { "id": 3 }, "color": 30 },
              { "motor": { "id": 4 }, "color": 40 }
            ]
          }
        ]
      },
      { "brand": [{ "model": [{ "size": 400 }] }] },
      { "brand": [{ "model": [{ "size": 500 }] }] }
    ],

The first array must contain the model with the motor and the colors. The second should only contain the brand with the size (I can have an indeterminate number of brands).

I would like this as an output:

    "carList": [
      {
        "brand": [
          {
            "model": [
              { "motor": { "id": 1 }, "color": 10 },
              { "motor": { "id": 2 }, "color": 20 },
              { "motor": { "id": 3 }, "color": 30 },
              { "motor": { "id": 4 }, "color": 40 }
            ]
          }
        ]
      },
    ],

    "carList": [
      { "brand": [{ "model": [{ "size": 400 }] }] },
      { "brand": [{ "model": [{ "size": 500 }] }] }
    ],

When trying to split the array, I tried to create the array only with size, but I get the carList global:

const carList1 = carList.filter((x) =>
    x.brand.filter((y) => y.model.filter((z) => z.size)
   );

How I can split my array and get this output?

UPDATE This is my more genral exemple test I can have many brand and model,

   "carList": [
      {
        "brand": [
          {
            "model": [
              { "motor": { "id": 1 }, "color": 10 },
              { "motor": { "id": 2 }, "color": 20 },
              { "motor": { "id": 3 }, "color": 30 },
              { "motor": { "id": 4 }, "color": 40 }
            ]
          },
          {
            "model": [
              { "motor": { "id": 1 }, "color": 11 },
              { "motor": { "id": 2 }, "color": 22 },
              { "motor": { "id": 3 }, "color": 33 },
              { "motor": { "id": 4 }, "color": 44 }
            ]
          }
        ]
      },
      { "brand": [
         { 
           "model": [
             { "size": 400 },
           ]
         },
         {
            "model": [
             { "size": 401 }
           ]
         },
      { "brand": [{ "model": [{ "size": 500 }] }] }
    ],

Carsten Massmann · Accepted Answer · 2022-05-06 19:00:34Z

1

This would be one way of doing it:

const data={"carList":[
   {"brand":[{"model": [{ "motor": { "id": 1 }, "color": 10 },
                        { "motor": { "id": 2 }, "color": 20 },
                        { "motor": { "id": 3 }, "color": 30 },
                        { "motor": { "id": 4 }, "color": 40 }]},
             {"model": [{ "motor": { "id": 1 }, "color": 11 },
                        { "motor": { "id": 2 }, "color": 22 },
                        { "motor": { "id": 3 }, "color": 33 },
                        { "motor": { "id": 4 }, "color": 44 }]}
            ]},
   {"brand":[{"model": [{ "size": 400 }]},
             {"model": [{ "size": 401 }]}]},
   {"brand":[{"model": [{ "size": 500 }]}]} 
]}

const [mo,si]=["motor","size"].map(p=>data.carList.filter(e=>
  e.brand.find(b=>b.model.find(m=>m[p]))));

console.log(JSON.stringify(mo));
console.log(JSON.stringify(si));

I applied the snippet now to the updated data. The result arrays motor and sizes are calculated by applying a .filter() on the data array.

In this updated version of the script I assign a brand to the mo or si array if it somehow contains the property motor or size`.

edited May 6, 2022 at 19:00

answered May 6, 2022 at 14:50

Carsten Massmann

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5 Comments

Heptagram Over a year ago

Yes its works but if i have two models in the brand like that :

Carsten Massmann Over a year ago

Could you maybe extend your sample data to show this more general test case and explain exactly what you would like to happen, if in one brand branch we should find both, a motor and a size type model.

Heptagram Over a year ago

I update my exemple with the more general test case

Heptagram Over a year ago

I can have a number inderterminate of model, brand, i must loop on the brand

Heptagram Over a year ago

thank you @Carsten Massmann, it's perfect i can adapt for my project

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