I want to replace every second occurence of a character from only a string as input. Using only the .replace method.
For example:
input: asdasdasdasd
output should be: asdASDasdasd
def main(string):
for char in string:
string.replace(char, char.upper())
return string
Im relatively new to Python and I can't wrap my head around what to do.
Alternatively, you can use a dictionary and make the second occurrence of each character to uppercase:
def upper_case_second_occurrence(s):
d = {}
s = list(s)
for i, c in enumerate(s):
d[c] = d.get(c, 0) + 1
if d[c] == 2:
s[i] = c.upper()
return "".join(s)
if __name__ == "__main__":
print(upper_case_second_occurrence("aaa"))
print(upper_case_second_occurrence("aaaaaa"))
print(upper_case_second_occurrence("asdasdasdasd"))
Output:
aAa
aAaaaa
asdASDasdasd
str.replace mentions it replaces all or the first n occurrences of a character from a string with a new character docs.python.org/3/library/stdtypes.html#str.replace . I do not think you can only use replace method in your scenario.Try this one:
def main(s):
l = []
string = ''
y = True
for a in s:
if a in l and y:
string+=a.upper()
l.remove(a)
if not len(l):
l = ''
continue
try:
l.append(a)
except AttributeError:
y = False
string+=a
return(string)
print(main('asdasdasdasd')) # → asdASDasdasd
print(main('aaa')) # → aAa
print(main('aaaaa')) # → aAaaa
print(main('AAA') # → AAA
Try using .count():
def main(string):
new_string = ''
for char in string:
if new_string.lower().count(char) == 1: # This line checks if the count of char is 1 or not. If yes, then it appends the uppercase letter of char
new_string += char.upper()
else:
new_string += char
return new_string
Output:
main('asdasdasdasd')
'asdASDasdasd'
main('aaaaaa')
'aAaaaa'
main('aaa')
'aAa'
replacereturns a new stringinput_1="aaa", what is the expectedoutput_1? Ifinput_2="aaaaaa", what is the expectedoutput_2?