Using Array.prototype.every or Array.property.some depending on condition

Question

I'm trying to make a function to filter some data using OR/AND logical operator depending on what the user selects. That means I need to use Array.prototype.every (AND) or Array.property,some (OR) to fullfill my requirement.

To avoid code redundancy I was trying to do something like this:

const functionApplied = condition === 'ALL'
        ? myArray.every
        : myArray.some;

functionApplied(item =>  {
    ... aux code ...
})
functionApplied.call(item =>  {
    ... aux code ...
})

Is there an analogous way to do it like this?

I know I could do something like this, but I'm just curious about above sintax...

const auxFunction = (item) => {...};
if (condition === 'ALL') {
    myArray.every(item => auxFunction(item));
} else {
    myArray.some(item => auxFunction(item));
}

"I was trying to do something like this": please explain which problem you encountered with that approach. — trincot
– trincot, Commented May 12, 2022 at 16:25
The proper .call usage is functionApplied.call(myArray, item => { ... aux code ... }) since you need to supply the value for this. — VLAZ
– VLAZ, Commented May 12, 2022 at 16:26

TKoL · Accepted Answer · 2022-05-12 16:30:23Z

1

You can definitely do something similar to what you're hoping to achieve. Here's one way:

function checkCondition(condition, booleanFunc, myArray) {
    const functionApplied = condition === 'ALL'
        ? myArray.every.bind(myArray)
        : myArray.some.bind(myArray);

    return functionApplied(booleanFunc);
}

console.log(checkCondition('ANY', (item) => {return item > 2}, [1,4,5,6]));
console.log(checkCondition('ANY', (item) => {return item > 2}, [4,5,6]));
console.log(checkCondition('ANY', (item) => {return item > 2}, [1,2]));
console.log(checkCondition('ALL', (item) => {return item > 2}, [1,4,5,6]));
console.log(checkCondition('ALL', (item) => {return item > 2}, [4,5,6]));

VLAZ comment is another good direction.

answered May 12, 2022 at 16:30

TKoL

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Comments

Ray · Accepted Answer · 2022-05-12 16:34:34Z

0

Yep, VLAZ comment is the way I wanted, this works:

const functionApplied = condition === 'ALL'
        ? Array.prototype.every
        : Array.prototype.some;

functionApplied.call(myArray, item =>  {
    ... aux code

Thanks everyone for your quick answers :)

answered May 12, 2022 at 16:34

Ray

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Comments

3limin4t0r · Accepted Answer · 2022-05-12 16:35:57Z

0

I would personally use the following:

const fn = condition === 'ALL' ? "every" : "some";
const result = myArray[fn]((item) => {
  // ... aux code ...
});

Storing the function name every or some in a variable called fn. Then calling it supplying your aux code.

answered May 12, 2022 at 16:35

3limin4t0r

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Barmar · Accepted Answer · 2022-05-12 16:37:14Z

0

You can use a variable holding the property name, and then use dynamic property access.

function functionApplied(condition) {
  return functionApplied === 'ALL' ? 'every' : 'some';
}

let result = myArray[functionApplied(condition)](item => { ... });

answered May 12, 2022 at 16:37

Barmar

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player's arena · Accepted Answer · 2022-05-25 13:58:47Z

0

const result = (myArray[condition === 'ALL' ? 'every': 'some'])(item => auxFunction(item))

this is minimal one line answer you can find

feel free to to seprate condition and min looping function

edited May 25, 2022 at 13:58

answered May 12, 2022 at 16:35

player's arena

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