Javascript variable undefined outside if else condition [duplicate]

Question

I have 2 objects coming from props and I am assigning these objects to their variable by if else condition

  let var1;
  let var2;

    if (props.id === 1) {
      var1 = props;
      console.log(var1); //  returns {id:1,learn:"HTML", do:"cooking"}
    } else {
      var2 = props;
    }

  console.log(var1); // returns {id:1,learn:"HTML", do:"cooking"} and undefined

When I console.log after condition why does it returns the object and undefined? But when console.log inside if condition only returns the object.

I want that it returns only the object if console.log after the condition

My two objects coming like this

{id:1,learn:"HTML", do:"cooking"}
{id:2,learn:"Css", do:"home-work"}

I have seen resources from StackOverflow

Javascript variable is undefined outside if condition

JavaScript Variable undefined outside of function

This question is said to be duplicate for Chrome/Firefox console.log always appends a line saying 'undefined'

but it's completely different it's not about the browsers console I am getting undefined from my javascript file

Where are you seeing the undefined? How are you executing this code? — Bergi
– Bergi, Commented May 17, 2022 at 21:09
@Bergi when I console the var1 after condition then I see the undefined in the console — program
– program, Commented May 17, 2022 at 21:13
You don't define it in all cases. If props.id is not 1, var1 does not get defined. — mykaf
– mykaf, Commented May 17, 2022 at 21:15
I am sorry that's a mistake that I make while asking the question. I will correct it — program
– program, Commented May 17, 2022 at 21:19

usman mughal · Accepted Answer · 2022-05-17 20:50:47Z

-2

Use const instead of let and try to differentiate the logs of next render from the previous render like this

const var1;
const var2;

if (props.id === 1) {
  var1 = data;
  console.log(var1);
} else {
  var2 = data;
}
console.log(var1);
console.log("--------");

answered May 17, 2022 at 20:50

usman mughal

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1 Comment

program Over a year ago

we can not change the const variable it would give an error

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