Sort array object based on another array in javascript

Question

How can i sort and rearrange an array that looks like this

fields = [
  {
    uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
    field: new ObjectId("627f816d8443318c6aaa1220"
  },
  {
    uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
    field: new ObjectId("6283cb3ca573a56e11587c46"),
  }
]

to match the arrangement of this array:

order = [ '6283cb3ca573a56e11587c46', '627f816d8443318c6aaa1220' ]

Here is the output I’m looking for:

[
{
    uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
    field: new ObjectId("6283cb3ca573a56e11587c46"),
  },
  {
    uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
    field: new ObjectId("627f816d8443318c6aaa1220"),
  }
]

findIndex and sort but I am very confused

fields.sort((a: any, b: any) => order.indexOf(a.field) - order.indexOf(b.field)) // It does not work

Do both arrays always have the same length? Or could it happen, that the Object-Array (the one you want to sort) has more entries than the array of objectIds? — moronator
– moronator, Commented May 18, 2022 at 12:44

Amir MB · Accepted Answer · 2022-05-18 12:49:07Z

2

You need to use sort method on the array. And then compare the index of field on the order array.

const data = [
{
    uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
    field: "6283cb3ca573a56e11587c46",
    value: 'test val 6'
  },
  {
    uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
    field: "627f816d8443318c6aaa1220",
    value: ''
  }
]

const order = [ '6283cb3ca573a56e11587c46', '627f816d8443318c6aaa1220' ];

data.sort((a,b) => order.indexOf(a.field) - order.indexOf(b.field));
console.log(data);

Notice: ObjectId class is not defined here, so I changed it to string here for simplicity.

answered May 18, 2022 at 12:49

Amir MB

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5 Comments

Şahin Ersever Over a year ago

Its not working for me. Should i a.field conver objectid

Amir MB Over a year ago

@ŞahinErsever ObjectId class is not defined here, so I changed it to string here for simplicity. What is ObjectId class definition?

Şahin Ersever Over a year ago

data.field: new ObjectId("627f816d8443318c6aaa1220" from mongoose

Amir MB Over a year ago

@ŞahinErsever you should be able to use data.sort((a,b) => order.indexOf(a._id.toHexString()) - order.indexOf(b._id.toHexString()));

Şahin Ersever Over a year ago

.toHexString() it worked thank you very much

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