How do i filter roles in this array to return true when "Admin" is found?
const array = [{
"country": "all",
"roles": [
"Normal",
"Admin",
]
}]
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3 Answers
Use .filter() and .includes():
const admins = array.filter((u) => u.roles.includes("Admin"))
Comments
1.Did u mean to return a boolean overall?
In Js es6, you could use .some() MDN web docs
it's nice and simple :)
const array = [{
"country": "all",
"roles": [
"Normal",
"Admin",
]
}, {
"country": "test",
"roles": [
"Normal"
]
}]
const result = array.some(o => Boolean(o.roles.some(role => role === 'Admin')))
console.log(result) // return true2.Or, did u mean that it returns a new array in which each roles become a boolean depending on having 'Admin' or not?
If it is, .some() works as well :)
Try below:
const array = [{
"country": "all",
"roles": [
"Normal",
"Admin",
]
}, {
"country": "test",
"roles": [
"Normal"
]
}]
const result = array.reduce((acc, curr, index) => {
const item = Object.assign({}, curr, { roles: curr.roles.some(o => o === 'Admin') })
acc.push(item)
return acc
}, [])
console.log(result) // return trueor if it filter an array, my answer is the same as Tobias' :)
Comments
const array = [{
"country": "all",
"roles": [
"Normal",
"Admin",
]
}]
const val = array.map((a) => a.roles.includes('Admin'))
console.log(val) //return true
Comments
