Accessing an array in JSON object in javascript

Question

I have the following JSON object in javascript returned by a PHP web service :

data={
"result": "pass",
"error_type": "",
"feedback_ids": {
    "feedback0": "1",
    "feedback1": "8"
},
"redirect_uri": ""
}

alert(data.result) works like a peach. How do I access "feedback_ids" and alert feedback0 and feedback1?

may be u havent parsed the JSON. Parse the JSON and then try it . var parsedObj = JSON.parse(data) ; alert(parsedObj.result); — user844866
– user844866, Commented Mar 5, 2013 at 19:49

momo · Accepted Answer · 2011-08-31 03:52:42Z

1

To access those variables you need to do:

data.feedback_ids.feedback0

and

data.feedback_ids.feedback1

If you have flexibility on server, make your life easier by changing that to JSON Array so you could loop them by their index. Note below I just changed the feedback_ids to the array structure

data={
"result": "pass",
"error_type": "",
"feedback_ids": [
    "1",
    "8"
],
"redirect_uri": ""
}

answered Aug 31, 2011 at 3:52

momo

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7 Comments

sniper Over a year ago

Hey Momo. I started with that! But everytime I alert it I am getting "undefined" as the result!!

momo Over a year ago

Did you try data.feedback_ids[0]?

sniper Over a year ago

I tried with the code I had as well as format you provided. Its still undefined.

sniper Over a year ago

This is the callback function from PHP : catch_merchant_feedback({"result":"pass","error_type":"","feedback_ids":["1","8"],"redirect_uri":""})

momo Over a year ago

Hmmm, I just tried that in Firebug Console and it worked. Have you tried loading the page with Firebug and just output it in the console to see what kind of JSON structure you are getting? If possible, maybe post the client' side code as well

|

mu is too short · Accepted Answer · 2011-08-31 03:49:20Z

1

To get at the feedback_ids:

ids = data.feedback_ids;

And to get inside that:

one   = data.feedback_ids.feedback0;
eight = data.feedback_ids.feedback1;

You could also use array notation:

one = data['feedback_ids']['feedback0'];

answered Aug 31, 2011 at 3:49

mu is too short

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1 Comment

sniper Over a year ago

I am getting "undefined" when I try to alert the data. What am I doing wrong? I am very sure that the data is present!

Brian Glaz · Accepted Answer · 2011-08-31 03:49:31Z

0

data.feedback_ids.feedback0 and data.feedback_ids.feedback1

answered Aug 31, 2011 at 3:49

Brian Glaz

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Comments

bjornd · Accepted Answer · 2011-08-31 03:50:03Z

0

for (var k in data.feedback_ids) {
    console.log(k, data.feedback_ids[k]); 
}

This code will output:

feedback0, 1
feedback1, 8

answered Aug 31, 2011 at 3:50

bjornd

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