Call Method of JavaScript Not Returning Correct Value

Question

const flightName = {
  airline: 'luftansa',
  itaCode: 'LH',
  book: function(flightname, text) {
    console.log(`This is ${flightname},${text}`);
  }
}

flightName.book('indigo', 'johnny');

let book1 = flightName.book;

book1.call('Johnny', 'King');

Output:

This is indigo,johnny

This is King,undefined

This seems familiar, are you watching course on Udemy by Jonas? :) — aca
– aca, Commented Jun 8, 2022 at 7:19
No, it's working perfectly. See developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — jonrsharpe
– jonrsharpe, Commented Jun 8, 2022 at 7:19
I don't think so, the output should be like This is indigo,johnny This is Johnny,King — Hitesh
– Hitesh, Commented Jun 8, 2022 at 7:21
The first argument to call is not the first argument of the called function. Read the documentation. — deceze
– deceze ♦, Commented Jun 8, 2022 at 7:22

mak15 · Accepted Answer · 2022-06-08 07:21:38Z

2

Try this

const flightName ={

airline: 'luftansa',

itaCode: 'LH',

book: function(flightname,text)
{

console.log(`This is ${flightname},${text}`);
}

}

flightName.book('indigo','johnny');

let book1 = flightName.book;

book1.call(this, 'Johnny','King');

answered Jun 8, 2022 at 7:21

mak15

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Comments

Mamdasan · Accepted Answer · 2022-06-08 07:26:16Z

2

you are calling your call funciton inccorect, call function is not supposed to work that way, as document stated: you should use it in this manner:

call()
call(thisArg)
call(thisArg, arg1)
call(thisArg, arg1, arg2)

so you need to change your code to:

book1.call(flightName,'johny', 'king');

answered Jun 8, 2022 at 7:26

Mamdasan

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