Error in inputting array and outputting it | Kotlin

Question

I am new at Kotlin (and my English is terrible :). I want to define the size of the array and elements in it by inputting it from the keyboard.

fun main() {
   val array_size = readLine()!!.toInt()
   val arr = IntArray(array_size)
   for (i in 0..array_size){
       arr[i] = readLine()!!.toInt()
   }
   
   for(i in 0..array_size){
       println(arr[i])
   }
}

[I got this message][1] [1]: https://i.sstatic.net/DRk9F.png This is my first question in StackOverFlow tho, hope it is understandable for those who want to help.

Please copy-paste the error message itself instead of pasting a screenshot: meta.stackoverflow.com/a/285557/1540818 — Joffrey
– Joffrey, Commented Jun 8, 2022 at 14:13

k314159 · Accepted Answer · 2022-06-08 14:22:50Z

3

The NullPointerException is probably because the call to readLine() is returning null and then you're forcing that to non-null using readLine()!! which gives you the NPE.

In recent versions of Kotlin a new method was introduced: readln(). It is recommended to use that instead of the old readLine. If and END OF FILE is found, the new readln method will throw a more descriptive exception, whereas readLine will return null which makes it more difficult to see where you went wrong.

You might get an end-of-file condition if the input is redirected from a file or other source. This often happens if you run your program in an IDE or an online compiler service. If you run your program from the command line, it will work, until you get to enter the last line. This is because for(i in 0..array_size) includes the value array_size which is 1 more than the last index, so you get an out-of-bounds exception.

Instead of using 0..(array_size - 1), it is recommended to use arr.indices which gives you the range of valid indices for the array.

answered Jun 8, 2022 at 14:22

k314159

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1 Comment

Madiyar Zhunusov Over a year ago

Thank you! It's very cool that the community here answers so fast.

Can_of_awe · Accepted Answer · 2022-06-08 14:21:42Z

1

readLine() is returning null, and so when you do readLine!!... you're getting a NullPointerException. Perhaps you want to use readln instead.

answered Jun 8, 2022 at 14:21

Can_of_awe

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1 Comment

Madiyar Zhunusov Over a year ago

Appreciate it!!

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