Is transferring JSON data in Django possible without JS / JQuery?

Question

I am learning how to handle JSON files in Django and I have successfully unpacked JSON, but now I would like to put it inside the table.

Is there a way to do that with pure HTML and using so called "tornado brackets" {{ }} not with jQuery / JS functions?

My code:

API BACKEND FILE

from requests import get


default_values = {
    "repoName": "",
    "repoURL": ""
    }

def get_response():
    response = get_json()

    main_dictionary = {
        "items":[]
    }

    try:
        for repos in response:
            main_dictionary["items"].append({
                "repoName": repos["name"],
                "repoURL": repos["html_url"]
                })

    except KeyError as error:
        print("Key Error, check the validity of the keys you try to use to decode JSON")

    return main_dictionary["items"]


def get_json():
    first_response = get('https://api.github.com/users/jacobtoye/repos')

    response = first_response.json()

    return response

A FAILED ATTEMPT AT RENDERING PURE HTML TABLE

{% block content %}

<table>
    <tr>
{% for repos in response %}
        <td>{{ repoName }}</td>
    {% if not forloop.last and forloop.counter == 3 or forloop.counter == 6 %}
    </tr>
    {% endif %}
    <tr>
{% endfor %}
    </tr>
</table>

The table doesn't show at all. I don't think that any other code files are substantial for this problem, but if you think you need more code, LMK I will gladly show you :)

You will need JSON.parse() to use the JSON response in the frontend and for that, you would javascript — Kavi Harjani
– Kavi Harjani, Commented Jun 12, 2022 at 14:40

NixonSparrow · Accepted Answer · 2022-06-12 14:48:50Z

1

In Django's views you usually pass such values as context.

function based view:

def a_view(request):
    context = {
        'some_things': Thing.objects.all()
    }
    return render(request, 'your_template.html', context)

class based view:

class TheView(View):
    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['some_things'] = Thing.objects.all()
        return context

With any of given approaches in template it will work like this:

{% for thing in some_things %}
    {{ thing }}, {{ thing.id }}, {{ thing.get_related_things }}
{% endfor %}

answered Jun 12, 2022 at 14:48

NixonSparrow

6,4281 gold badge8 silver badges18 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Swantewit Over a year ago

You're an awesome person @NixonSparrow. Thank you. You helped me figure it out and not did it for me. There is a special place in heaven for people like you :)

NixonSparrow Over a year ago

I just had similar problems and sometimes can relate ;)

Swantewit Over a year ago

Still thanks for not doing this for me, but helping me grow <3

Collectives™ on Stack Overflow

Is transferring JSON data in Django possible without JS / JQuery?

1 Answer 1

3 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related