Replace particular character in a python string with multiple character and produce two different outputs

Question

Use case 1 :

str = '?0?'   #str is input string , we need to replace every '?' with [0,1].

so the resulting output will be :

['000','100','001','101']

use case 2 :

str = '?0' #input

Expected output :

['00','10']

use case 3 :

str='?'

Expected output :

['0','1']

The length of the string and number of '?' in string may vary for different inputs.

Are you aware of the differences between strings and integers? Your question suggest you are not, so you may want to read up on beginners tutorials on that. — 9769953
– 9769953, Commented Jun 14, 2022 at 6:00

Nick · Accepted Answer · 2022-06-14 06:04:02Z

1

Here's a solution using itertools.product to produce all possible products of [0,1] for a ? or the digit itself:

str = '?0?'
[''.join(p) for p in itertools.product(*[['0', '1'] if c == '?' else c for c in str])]

Output:

['000', '001', '100', '101']

answered Jun 14, 2022 at 6:04

Nick

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1 Comment

sudarsan Over a year ago

Thanks for your solution , it is exactly what i am looking for. I am new to the python collections framework , will explore more on itertools to handle similar kind of problems.

Kelly Bundy · Accepted Answer · 2022-06-14 06:13:23Z

0

Without itertools:

s = '?0?'

a = ['']
for c in s:
    a = [b+d for b in a for d in c.replace('?', '01')]

print(a)

Try it online!

answered Jun 14, 2022 at 6:13

Kelly Bundy

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