Lambda function with loop and condition

Question

I have a column in Pandas DataFrame which I would like to process for all rows.

Example:

df_column:
    0     urewjf, abc, urewurwe
    1     fdsfs, kjf, oirpiewpoirew...
    2     ab, yryrewy, popof...

What I want to do with thouse values:

add blank space in the beginning of the strings which have len<4 EXAMPLE: ' abc', ' ab'

I was trying to convert each row/Series into string and then run lambda function to apply it for each row:

list(map(lambda x: (x.rjust(5) for x in df.column if len(x) < 4), df.column))

It was not working.

Also, I have issues when I use .apply() because of the Series type, but apparantly my lambda function is not constructed correctly.

Any ideas? Thank you in advance

urewjf, abc, urewurwe is this a row of a column or a row of more columns? — solid
– solid, Commented Jun 16, 2022 at 12:33

Vovin · Accepted Answer · 2022-06-16 12:56:26Z

2

You can just use a pandas vectorised string methods:

df.<your_column_name> = df.<your_column_name>.str.rjust(5)

edited Jun 16, 2022 at 12:56

answered Jun 16, 2022 at 12:39

Vovin

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Comments

solid · Accepted Answer · 2022-06-16 12:40:37Z

0

df = pd.DataFrame({
    "TX_F1": [
        "urewjf",
        "fdsfs",
    ],
    "TX_F2": [
        "abc",
        "kjf"
    ]
})

df.applymap(lambda x: str(x).rjust(5))

answered Jun 16, 2022 at 12:40

solid

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