Remove leading zeros from a string using regex

Question

I am learning regex and java and working on a problem related to that.

I have an input string which can be any dollar amount like

$123,456.78
$0012,345.67
$123,04.56
$123,45.06

it also could be

$0.1

I am trying to find if the dollar amount has leading zeros and trying to remove it.

so far I have tried this

string result = input_string.replaceAll(("[!^0]+)" , "");

But I guess I'm doing something wrong. I just want to remove the leading zeros, not the ones between the amount part and not the one in cents. And if the amount is $0.1, I don't want to remove it.

Thanks @WiktorStribiżew, that worked with all requirements! :) — adamn2
– adamn2, Commented Jun 16, 2022 at 21:48

Bohemian · Accepted Answer · 2022-06-17 03:36:32Z

4

Match zeroes or commas that are preceded by a dollar sign and followed by a digit:

str = str.replaceAll("(?<=\\$)[0,]+(?=\\d)", "");

See live demo.

This covers the edge cases:

$001.23 -> $1.23
$000.12 -> $0.12
$00,123.45 -> $123.45
$0,000,000.12 -> $0.12

The regex:

(?<=\\$) means the preceding character is a dollar sign
(?=\\d) means the following character is a digit
[0,]+ means one or more zeroes or commas

To handle any currency symbol:

str = str.replaceAll("(?<=[^\\d,.])[0,]+(?=\\d)", "");

See live demo.

edited Jun 17, 2022 at 3:36

answered Jun 16, 2022 at 21:48

Bohemian♦

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The fourth bird · Accepted Answer · 2022-06-17 08:27:20Z

1

You can use

string result = input_string.replaceFirst("(?<=\\p{Sc})[0,]+(?=\\d)", "");

See the regex demo.

Details:

(?<=\p{Sc}) - immediately on the left, there must be any currency char
[0,]+ - one or more zeros or commas
(?=\d) - immediately on the right, there must be any one digit.

edited Jun 17, 2022 at 8:27

The fourth bird

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answered Jun 16, 2022 at 21:49

Wiktor Stribiżew

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Comments

Tydal · Accepted Answer · 2022-06-16 22:25:52Z

0

This is a simple regex that fits your needs:

str = str.replaceAll("^[$][,0]+0(?![.])", "$");

edited Jun 16, 2022 at 22:25

answered Jun 16, 2022 at 22:03

Tydal

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