How to sort nested dictionaries in python

Question

This is a most common question to be asked but with different use case

I have some dictionary structure in place as the below.

dict_1 = {
    'c': {
        'c3': [],
        'c1': [],
        'c2': []
    },
    'a': {
        'a3': [],
        'a1': [],
        'a2': []
    },
    'b': {
        'b3': [],
        'b1': [],
        'b2': []
    },
}

I want to sort it on two levels

first sort dictionary at Level1 by keys at Level1
sort dictionary at by keys at Level2

i.e, after the sorting the output should be as

dict_1 = {
    'a': {
        'a1': [],
        'a2': [],
        'a3': []
    },
    'b': {
        'b1': [],
        'b2': [],
        'b3': []
    },
    'c': {
        'c1': [],
        'c2': [],
        'c3': []
    },
}

I am able to do it in two steps, first sorting the dictionary at Level1 by keys. Then iterating the dictionary and again sorting the dictionary at level2 by keys again.

Is their pythonic way to achieve the same in one sorting ?

I managed to sort the above as

dict_1 = {k: {k1: v1 for k1, v1 in sorted(v.items(), key=lambda level_2_dict: level_2_dict[0])}
          for k, v in sorted(dict_1.items(), key=lambda level_1_dict: level_1_dict[0])}

print(dict_1)

# output 
{'a': {'a1': [], 'a2': [], 'a3': []}, 'b': {'b1': [], 'b2': [], 'b3': []}, 'c': {'c1': [], 'c2': [], 'c3': []}}

BhusalC_Bipin · Accepted Answer · 2022-06-18 21:49:25Z

2

dict_1 = {key: dict(sorted(dict_1[key].items())) for key in sorted(dict_1)}

>>> print(dict_1)
>>> {'a': {'a1': [], 'a2': [], 'a3': []}, 'b': {'b1': [], 'b2': [], 'b3': []}, 'c': {'c1': [], 'c2': [], 'c3': []}}

edited Jun 18, 2022 at 21:49

answered Jun 18, 2022 at 21:38

BhusalC_Bipin

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