I have this String p="V755D888B154" and i want to split it to have this form
- V
- 755
- D
- 888
- B
- 154
How can i do it ? thanks in advance
2
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2Are you always going to have three letters and three numbers between 100 and 999? Regex may be one way to go. Java substring may be another if the character positions are fixed.rajah9– rajah92011-09-01 22:07:28 +00:00Commented Sep 1, 2011 at 22:07
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The letters are fixed but the numbers aren't , and yes they are between 100 and 999Neek– Neek2011-09-01 22:11:38 +00:00Commented Sep 1, 2011 at 22:11
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3 Answers
You can use String.split. Example:
String[] numbers = p.split("[a-zA-Z]+");
String[] letters = p.split("[0-9]+");
numbers or letters can have empty string, but you can check it manually.
1 Comment
Neek
That really worked it separated the string and the numbers like i've wanted . thank you and also so many thanks and respect for the other answers ! i have so much respect for what you do here trying helps us , we the newbies :)
If your string contains only numbers and strings this snippets workes
String string = "V755D888B154";
Pattern p = Pattern.compile("\\d+|\\D+");
Matcher matcher = p.matcher(string);
while(matcher.find()) {
Integer i = null;
String s = null;
try {
i = Integer.parseInt(matcher.group());
}
catch (NumberFormatException nfe) {
s = matcher.group();
}
if (i != null) System.out.println("NUMBER: " + i);
if (s != null) System.out.println("STRING: " + s);
}
main fail is checking if given String (matcher.group()) consist Integer or not
Comments
In your comment you say the letters are fixed, so you if you're just trying to pull out the numbers you could always do something like this. I'll leave it up to you if you think this is a kluge.
String p="V755D888B154";
Integer vPart = Integer.valueOf(p.substring(1,4));
Integer dPart = Integer.valueOf(p.substring(5,8));
Integer bPart = Integer.valueOf(p.substring(9,12));
System.out.println(bPart);
