How to pass variable from view.py to javascript without using render() in django

Question

return render(request, 'index.html', {"flag": flag, "form": form})

I want to pass flag value which should be read by javascript to change style of an element in template, but since rendering it again the flag value is lost and set back to "none" ,is there any way to not use render and pass the variable to a url where the page is already rendered

 $.ajax({
            type: "GET",
            url: "/home", //url of site no need to enter full site
           dataType: "json",


            contentType: 'application/json',

            success: function (response) {
             
                  alert(response.flag);

// Gives value of flag
            },

            error: function (response) {
               alert('error');
            }
        });

update : i tried this code but it always goes into error session and doesnt get into success block

What do you mean by rendering it again? does it mean reloading the page? — Vinay Kumar
– Vinay Kumar, Commented Jun 28, 2022 at 1:16

Pujan Bade · Accepted Answer · 2022-06-28 02:47:56Z

1

In your javascript file use ajax method to call your views.py, 

   $.ajax({
            type: "GET", method GET or POST
            url: "/url_name/", //url of site no need to enter full site

            data: {
                'key': value, // data you want to pass if any
            },

            contentType: 'application/json',

            success: function (response) {
                  console.log(response.flag) // Gives value of flag  
            },

            error: function (data) {
                console.log('error');
            }
        });;

In your views.py you can pass your flag value as JSON response,

    def view_name(response):
        return JsonResponse({'flag': flag }, content_type='application/json')

answered Jun 28, 2022 at 2:47

Pujan Bade

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2 Comments

Allen Anand Over a year ago

i tried this but couldnt get it working, i am passing flag="accept"/flag="reject" as {"flag": flag}

Pujan Bade Over a year ago

def view_name(request): # Use request instead of response

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