630

Imagine this directory structure:

app/
   __init__.py
   sub1/
      __init__.py
      mod1.py
   sub2/
      __init__.py
      mod2.py

I'm coding mod1, and I need to import something from mod2. How should I do it?

I tried from ..sub2 import mod2, but I'm getting an "Attempted relative import in non-package".

I googled around, but I found only "sys.path manipulation" hacks. Isn't there a clean way?


All my __init__.py's are currently empty

I'm trying to do this because sub2 contains classes that are shared across sub packages (sub1, subX, etc.).

The behaviour I'm looking for is the same as described in PEP 366 (thanks John B).

4
  • 9
    I recommend updating your question to make it more clear that you're describing the issue addressed in PEP 366. Commented Sep 16, 2008 at 19:36
  • 2
    It's a long winded explanation but check here: stackoverflow.com/a/10713254/1267156 I answered a very similar question. I had this same problem until last night. Commented May 23, 2012 at 4:05
  • 3
    For those who wish to load a module located at an arbitrary path, see this: stackoverflow.com/questions/67631/… Commented Jun 8, 2014 at 6:29
  • 2
    On a related note, Python 3 will change the default handling of imports to be absolute by default; relative imports will have to be explicitly specified. Commented Mar 30, 2015 at 23:28

17 Answers 17

389

The problem is that you're running the module as '__main__' by passing the mod1.py as an argument to the interpreter.

From PEP 328:

Relative imports use a module's __name__ attribute to determine that module's position in the package hierarchy. If the module's name does not contain any package information (e.g. it is set to '__main__') then relative imports are resolved as if the module were a top level module, regardless of where the module is actually located on the file system.

In Python 2.6, they're adding the ability to reference modules relative to the main module. PEP 366 describes the change.

Sign up to request clarification or add additional context in comments.

11 Comments

The recommended alternative is to run modules inside packages using the -m switch, rather than by specifying their filename directly.
I don't understand: where is the answer here? How can one import modules in such a directory structure?
@Tom: In this instance, mod1 would from sub2 import mod2. Then, to run mod1, from within app, do python -m sub1.mod1.
@XiongChiamiov: does this mean you can't do it if your python is embedded in an application, so you don't have access to python command line switches?
"Everyone seems to want to tell you what you should be doing rather than just answering the question." Well, good. That's the way getting help writing software should be! When I fly in the face of good practice, I want to know.
|
170

Here is the solution which works for me:

I do the relative imports as from ..sub2 import mod2 and then, if I want to run mod1.py then I go to the parent directory of app and run the module using the python -m switch as python -m app.sub1.mod1.

The real reason why this problem occurs with relative imports, is that relative imports works by taking the __name__ property of the module. If the module is being directly run, then __name__ is set to __main__ and it doesn't contain any information about package structure. And, thats why python complains about the relative import in non-package error.

So, by using the -m switch you provide the package structure information to python, through which it can resolve the relative imports successfully.

I have encountered this problem many times while doing relative imports. And, after reading all the previous answers, I was still not able to figure out how to solve it, in a clean way, without needing to put boilerplate code in all files. (Though some of the comments were really helpful, thanks to @ncoghlan and @XiongChiamiov)

Hope this helps someone who is fighting with relative imports problem, because going through PEP is really not fun.

4 Comments

Best answer IMHO: not only explains why OP had the issue, but also finds a way to solve it without changing the way his modules do imports. Afterall, OP's relative imports were fine. The culprit was the lack of access to outer packages when directly running as script, something -m was designed to solve.
Also take note: this answer was 5 years after the question. These features were not available at the time.
If you want to import a module from the same directory you can do from . import some_module.
This is the answer that helped me and it also helped me condense my thought down to this: In order to run a Python script which contains relative imports, I must run the script as a module while $ PWD is its parent directory like $ python -m app.main. For clarity, $ python -m <main_directory>.<script_with_relative_imports>
133
main.py
setup.py
app/ ->
    __init__.py
    package_a/ ->
       __init__.py
       module_a.py
    package_b/ ->
       __init__.py
       module_b.py
  1. You run python main.py.
  2. main.py does: import app.package_a.module_a
  3. module_a.py does import app.package_b.module_b

Alternatively 2 or 3 could use: from app.package_a import module_a

That will work as long as you have app in your PYTHONPATH. main.py could be anywhere then.

So you write a setup.py to copy (install) the whole app package and subpackages to the target system's python folders, and main.py to target system's script folders.

3 Comments

Excellent answer. Is there some way to import that way without install the package in PYTHONPATH?
then, one day, need to change name of app to test_app. what would happen? You will need to change all the source codes, import app.package_b.module_b --> test_app.package_b.module_b. this is absolutely BAD practice... And we should try to use relative import within the package.
55

"Guido views running scripts within a package as an anti-pattern" (rejected PEP-3122)

I have spent so much time trying to find a solution, reading related posts here on Stack Overflow and saying to myself "there must be a better way!". Looks like there is not.

3 Comments

Note: Already mentioned pep-366 (created around the same time as pep-3122) provides the same capabilities but uses a different backward-compatible implementation i.e., if you want to run a module inside a package as a script and use explicit relative imports in it then you could run it using -m switch: python -m app.sub1.mod1 or invoke app.sub1.mod1.main() from a top-level script (e.g., generated from setuptools' entry_points defined in setup.py).
+1 for using setuptools and entry points - it is a proper way to set up scripts that will be run from the outside, in a well-defined location, as opposed to endlessly hacking PYTHONPATH
Didn't found the definition of 'run' on the peps. For me, it doesn't look like 'running' is the best definition (for the ant pattern) cause at the end the 'interpretation' will link the dependencies and not actually 'run' it at the sense of executing immediately. Reference 1 and reference 2
48

This is solved 100%:

  • app/
    • main.py
  • settings/
    • local_setings.py

Import settings/local_setting.py in app/main.py:

main.py:

import sys
sys.path.insert(0, "../settings")


try:
    from local_settings import *
except ImportError:
    print('No Import')

3 Comments

thank you! all ppl were forcing me to run my script differently instead of telling me how to solve it within script. But I had to change the code to use sys.path.insert(0, "../settings") and then from local_settings import *
Can you explain your answer, please? For example, why does it work? How does it work? What is the gist? "Explanation is vital for a good answer."_. (But ***** ***** ***** without ***** ***** ***** "Edit:", "Update:", or similar - the answer should appear as if it was written today)
@PeterMortensen it works because it's a hack. Python uses the path to look for modules. By default, the directory of where the script is executed from is in the path. This forces the directory that is up one level, called settings is inserted into that path. Like all hacks, this will work in a lot of situations but it's not how imports are intended to work in Python. Other methods are preferred
29

Explanation of nosklo's answer with examples:

Note: all __init__.py files are empty.

main.py
app/ ->
    __init__.py
    package_a/ ->
       __init__.py
       fun_a.py
    package_b/ ->
       __init__.py
       fun_b.py

app/package_a/fun_a.py

def print_a():
    print 'This is a function in dir package_a'

app/package_b/fun_b.py

from app.package_a.fun_a import print_a
def print_b():
    print 'This is a function in dir package_b'
    print 'going to call a function in dir package_a'
    print '-'*30
    print_a()

main.py

from app.package_b import fun_b
fun_b.print_b()

If you run python main.py it returns:

This is a function in dir package_b
going to call a function in dir package_a
------------------------------
This is a function in dir package_a
  • main.py does: from app.package_b import fun_b
  • fun_b.py does from app.package_a.fun_a import print_a

so file in folder package_b used file in folder package_a, which is what you want. Right??

1 Comment

This does not answer the question. The question is how to do relative imports; this shows only absolute imports.
24

Use:

def import_path(fullpath):
    """ 
    Import a file with full path specification. Allows one to
    import from anywhere, something __import__ does not do. 
    """
    path, filename = os.path.split(fullpath)
    filename, ext = os.path.splitext(filename)
    sys.path.append(path)
    module = __import__(filename)
    reload(module) # Might be out of date
    del sys.path[-1]
    return module

I'm using this snippet to import modules from paths.

5 Comments

I'm using this snippet, combined with the imp module (as explained here [1]) to great effect. [1]: stackoverflow.com/questions/1096216/…
Probably, sys.path.append(path) should be replaced with sys.path.insert(0, path), and sys.path[-1] should be replaced with sys.path[0]. Otherwise the function will import the wrong module, if there is already a module with the same name in search path. E.g., if there is "some.py" in current dir, import_path("/imports/some.py") will import the wrong file.
I agree! Sometimes other relative imports will make precedance. Use sys.path.insert
How would you replicate the behavior of from x import y (or *)?
It's not clear, please specify full usage of this script to solve OP problem.
13

This is unfortunately a sys.path hack, but it works quite well.

I encountered this problem with another layer: I already had a module of the specified name, but it was the wrong module.

what I wanted to do was the following (the module I was working from was module3):

mymodule\
   __init__.py
   mymodule1\
      __init__.py
      mymodule1_1
   mymodule2\
      __init__.py
      mymodule2_1


import mymodule.mymodule1.mymodule1_1  

Note that I have already installed mymodule, but in my installation I do not have "mymodule1"

and I would get an ImportError because it was trying to import from my installed modules.

I tried to do a sys.path.append, and that didn't work. What did work was a sys.path.insert

if __name__ == '__main__':
    sys.path.insert(0, '../..')

So kind of a hack, but got it all to work! So keep in mind, if you want your decision to override other paths then you need to use sys.path.insert(0, pathname) to get it to work! This was a very frustrating sticking point for me, allot of people say to use the "append" function to sys.path, but that doesn't work if you already have a module defined (I find it very strange behavior)

2 Comments

sys.path.append('../') works fine for me (Python 3.5.2)
I think this is fine since it localizes the hack to the executable and doesn't affect other modules which may depend on your packages.
10

Let me just put this here for my own reference. I know that it is not good Python code, but I needed a script for a project I was working on and I wanted to put the script in a scripts directory.

import os.path
import sys
sys.path.append(os.path.abspath(os.path.join(os.path.dirname(__file__), "..")))

Comments

8

Take a look at http://docs.python.org/whatsnew/2.5.html#pep-328-absolute-and-relative-imports. You could do

from .mod1 import stuff

1 Comment

Except one can't do relative imports from the 'main' module as the answer from John B. states
8

As EvgeniSergeev says in the comments to the OP, you can import code from a .py file at an arbitrary location with:

import imp

foo = imp.load_source('module.name', '/path/to/file.py')
foo.MyClass()

This is taken from this SO answer.

1 Comment

This does not answer the question. The question is how to use relative imports correctly, not "please just enable me to import the file".
2

From Python doc,

In Python 2.5, you can switch import‘s behaviour to absolute imports using a from __future__ import absolute_import directive. This absolute- import behaviour will become the default in a future version (probably Python 2.7). Once absolute imports are the default, import string will always find the standard library’s version. It’s suggested that users should begin using absolute imports as much as possible, so it’s preferable to begin writing from pkg import string in your code

Comments

2

On top of what John B said, it seems like setting the __package__ variable should help, instead of changing __main__ which could screw up other things. But as far as I could test, it doesn't completely work as it should.

I have the same problem and neither PEP 328 nor PEP 366 solve the problem completely, as both, by the end of the day, need the head of the package to be included in sys.path, as far as I could understand.

Comments

1

I found it's easier to set the "PYTHONPATH" environment variable to the top folder:

bash$ export PYTHONPATH=/PATH/TO/APP

Then:

import sub1.func1
# ...more imports

Of course, PYTHONPATH is "global", but it didn't raise trouble for me yet.

Comments

0

A hacky way to do it is to append the current directory to the PATH at runtime as follows:

import pathlib   
import sys
sys.path.append(pathlib.Path(__file__).parent.resolve())
import file_to_import  # the actual intended import

In contrast to another solution for this question this uses pathlib instead of os.path.

Comments

0

I wrote a package to solve this nasty issue, Sysappend:

https://pypi.org/project/sysappend/

This appends every folder in your repository to the sys.path variable, so Python is able to import any folder.

If you use this package, you don't need to pollute your project with __init__.py files, and you will unlock relative imports (both parent and child folders) from anywhere, without all the fuss. You will get correctly working debug, test and deploy features without going mad. At the same time, you get correct type-hinting, syntax highlighting, and module highlights.

This package does require you to add a short one-liner to the top of all your Python files (it doesn't need to be all files -- but it's convenient and can be enforced with CI/CD, GitHub actions or simply added via a quick copy-paste).

In my opinion, this solves the super-nasty import and relative package management in an developer-friendly way which basic Python fails to deliver.

How to use it

  1. pip install sysappend
  2. Add an if True: import sysappend; sysappend.all() statement at the top of every python file in your repo. (It doesn't need to be every file, but it's just easier for convenience, and the function caches results avoiding redundant computation, so it doesn't slow the code down).

Recommended folder referencing when importing

You should always try to reference the folders in the same way.
For example, use one (or few) agreed-upon primary source code folder from which to reference the sub-directories and stick to that convention.

E.g., if your directory looks like the below, you could pick src to be the primary source code folder:

sample_project/
    src/
        sub_folder_1/
            utils.py
        sub_folder_2/
            models.py
    app.py

So, when you write imports, they should start from the primary src folder.

E.g., in your app.py file, you should do:

from src.sub_folder_1.utils import somefunction

and you should do the same thing in models.py:

from src.sub_folder_1.utils import somefunction

Do not use a sub_folder as a starting name for an import, i.e., do not do from sub_folder_1.utils import somefunction. Although it will may still work in most cases, it may fail when you do type comparisons or deserialization, as Python looks at the import path to compare/deserialize types.

Quality of life setting for editors like VSCode

If you're using an editor like VSCode, you may want to add the main primary source code folder(s) to your settings.json file, like:

    "python.autoComplete.extraPaths": [
        "./src",
    ]

This will help the autocomplete to reference the folders always starting from src, in the same way as explained above -- i.e., you won't get automatic completion that attempt to do imports from sub folders.

Comments

-2

What a debate!

I am a relative newcomer to Python (but years of programming experience, and dislike of Perl) and am a relative layperson when it comes to the dark art of Apache setup, but I know what I (think I) need to get my little experimental projects working at home.

Here is my summary of what the situation seems to be.

If I use the -m 'module' approach, I need to:

  1. dot it all together;
  2. run it from a parent folder;
  3. lose the '.py';
  4. create an empty (!) __init__.py file in every subfolder.

How does that work in a CGI environment, where I have aliased my scripts directory, and want to run a script directly as /dirAlias/cgi_script.py??

Why is amending sys.path a hack? The Python documentation page states: "A program is free to modify this list for its own purposes." If it works, it works, right? The bean counters in Accounts don't care how it works.

I just want to go up one level and down into a 'modules' directory:

.../py
      /cgi
      /build
      /modules

So my 'modules' can be imported from either the CGI world or the server world.

I've tried the -m/modules approach but I think I prefer the following (and am not confused how to run it in CGI space):

  1. Create XX_pathsetup.py in the /path/to/python/Lib directory (or any other directory in the default sys.path list). 'XX' is some identifier that declares an intent to set up my path according to the rules in the file.

  2. In any script that wants to be able to import from the 'modules' directory in above directory config, simply import XX_pathsetup.py.

And here's my really simple XX_pathsetup.py file:

import sys, os
pypath = sys.path[0].rsplit(os.sep, 1)[0]
sys.path.insert(0, pypath + os.sep + 'modules')

It is not a 'hack', IMHO. It is one small file to put in the Python 'Lib' directory and one import statement which declares intent to modify the path search order.

1 Comment

This answer is wrong on many levels. __init__.py files have not been required for marking packages since Python 3.3 and they are intended for a completely orthogonal purpose. They are never required to be empty; it's just less work to make an empty file than a non-empty one. Aside from that, please keep in mind that this is not a discussion forum and answers are expected to get directly to the point without talking about personal experiences or related problems you have tried to solve (please read How to Answer). Finally, why are you working directly with CGI in 2023?

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