Unable to unpack values in Python

Question

I have a dictionary say

a = { 'a': 'abc',
'b': 'xyz',
'c': 'yyy'

}

and another list of dictionaries say

list_dict = [{'id': 5903032523805, 'value': 'aaa'}, {'id': 5903031568925, 'value': 'bbb'}, {'id': 5902976332061, 'value': 'ccc'}]

How do I perform

for i, j in list_dict, a.values():
    print(i['id'], j)

Error: too many values to unpack (expected 2)

Now i'm aware that a.values returns dict_values[()] as individual items (iterate) as output and also i['id'] returns first dictionary id (1st item in list). But when combined in a for loop , unable to extract it. Any suggestions as to what I'm doing wrong?

Does this answer your question? python: ValueError: too many values to unpack (expected 2) — NelsonGon
– NelsonGon, Commented Jul 15, 2022 at 18:11
For an explanation of what's going on: What you've done here is create a tuple with the following structure: (dict, List[dict]), so it will unload the first element (the dict) but it expects 3 values instead of two since that's how many keys are in your dict. — Jevon Cowell
– Jevon Cowell, Commented Jul 15, 2022 at 18:16

Liju · Accepted Answer · 2022-07-15 18:10:03Z

2

Please try using zip.

for (i, j) in zip(list_dict, a.values()):
     print(i['id'], j)

Output:

5903032523805 abc
5903031568925 xyz
5902976332061 yyy

answered Jul 15, 2022 at 18:10

Liju

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1 Comment

Mahesh Manjunath Over a year ago

Thank you @Liju. I had studied about zip(zipping two datastructure values into one single tuple like ((,), (,)) but did not remember to use it here.

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