Python 3 simple HTTP server with GET functional

Question

I can't find any Python code for the equivalent of

python -m http.server port --bind addr --directory dir

I need a server class that processes at least GET requests. Most things I found were either an HTTP server with some special needs or something like that, where you need to code the response behaviour be yourself:

from http.server import BaseHTTPRequestHandler, HTTPServer

def run(server_class=HTTPServer, handler_class=BaseHTTPRequestHandler):
    server_address = ('', 8000)
    httpd = server_class(server_address, handler_class)
    httpd.serve_forever()

run()

I need a default working skeleton of a Python HTTP server, where you can provide address, port and directory, and it would normally process GET requests.

Community · Accepted Answer · 2024-11-19 10:53:04Z

4

You need to subclass the BaseHTTPRequestHandler to, well, handle the requests:

class HTTPRequestHandler(BaseHTTPRequestHandler):
    """HTTP request handler with additional properties and functions"""

    def do_GET(self):
        """Handle GET requests"""
        # Do something

edited Nov 19, 2024 at 10:53

CommunityBot

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answered Jul 23, 2022 at 10:46

user3515670

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3 Comments

sherwood Over a year ago

Yes, I know. But what code should be in this method to process simplest GET request, as for example apache2 doing it for default?

user3515670 Over a year ago

That entirely depends on what you want the method / web server to do.

sherwood Over a year ago

I already wrote. I want simple HTTP server. So I can browse directories and view web-pages with css and images. Means on GET request I will get headers with file body. The command I mentioned in the begging is working perfectly but I need code-based solution

Pat Myron · Accepted Answer · 2025-08-05 02:45:07Z

# python -m http.server 8000 --directory ./my_dir

from http.server import HTTPServer as BaseHTTPServer, SimpleHTTPRequestHandler
import os


class HTTPHandler(SimpleHTTPRequestHandler):
    """This handler uses server.base_path instead of always using os.getcwd()"""

    def translate_path(self, path):
        path = SimpleHTTPRequestHandler.translate_path(self, path)
        relpath = os.path.relpath(path, os.getcwd())
        fullpath = os.path.join(self.server.base_path, relpath)
        return fullpath


class HTTPServer(BaseHTTPServer):
    """The main server, you pass in base_path which is the path you want to serve requests from"""

    def __init__(self, base_path, server_address, RequestHandlerClass=HTTPHandler):
        self.base_path = base_path
        BaseHTTPServer.__init__(self, server_address, RequestHandlerClass)


web_dir = os.path.join(os.path.dirname(__file__), 'my_dir')
httpd = HTTPServer(web_dir, ("", 8000))
httpd.serve_forever()

A simple HTTP server that handles GET requests with, working with a certain directory.

Don Hatch · Accepted Answer · 2024-09-16 02:10:06Z

SimpleHTTPRequestHandler's constructor accepts an optional directory, although trying to get at it is torturous. Here's the simplest thing I came up with:

#!/usr/bin/python3

import http.server
import os
import sys

def MakeHandlerClassWithBakedInDirectory(directory):
  class Handler(http.server.SimpleHTTPRequestHandler):
    def __init__(self, *args, **kwargs):
      super().__init__(*args, **kwargs, directory=directory)
  return Handler

if len(sys.argv) != 3:
  exit("Usage: something <port> <directory>")

port = int(sys.argv[1])
directory = sys.argv[2]

assert os.path.isdir(directory), f"{directory!r} is not a directory"

with http.server.ThreadingHTTPServer(('', port), 
                                     MakeHandlerClassWithBakedInDirectory(directory)) as httpd:
  print(f"serving at port {port}")
  httpd.serve_forever()

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