Printing PHP Array into a string with correct syntax

Question

If I have this array:

<?php 

$myarray =  Array
                (
                        'keyword' => 'seo',
                        'title_factor' => false,
                        'description_factor' => false,
                        'headtags_factor' => false,
                        'imgalt_factor' => false,
                        'keyword_density' => 0,
                );


var_dump($myarray);
print_r($myarray);                      


?>

Here is the output of vardump and print_r:

array(6) {
  ["keyword"]=>
  string(3) "seo"
  ["title_factor"]=>
  bool(false)
  ["description_factor"]=>
  bool(false)
  ["headtags_factor"]=>
  bool(false)
  ["imgalt_factor"]=>
  bool(false)
  ["keyword_density"]=>
  int(0)
}
Array
(
    [keyword] => 'seo'
    [title_factor] => 
    [description_factor] => 
    [headtags_factor] => 
    [imgalt_factor] => 
    [keyword_density] => 0
)

Here is what I want as output:

    "Array
    (
            'keyword' => 'seo',
            'title_factor' => false,
            'description_factor' => false,
            'headtags_factor' => false,
            'imgalt_factor' => false,
            'keyword_density' => 0,
    );"

As seo does not seem to be a constant, you should change 'keyword' => seo, to 'keyword' => 'seo',. — str
– str, Commented Sep 6, 2011 at 8:21

Arnaud Le Blanc · Accepted Answer · 2011-09-06 08:13:54Z

43

Use var_export()^[docs]:

$string = var_export($array, true);

answered Sep 6, 2011 at 8:13

Arnaud Le Blanc

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Comments

Tom Vervoort · Accepted Answer · 2011-09-06 08:15:35Z

6

You're searching for var_export if I'm correct

more info about var_export at http://www.php.net/manual/en/function.var-export.php

answered Sep 6, 2011 at 8:15

Tom Vervoort

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1 Comment

Tom Vervoort Over a year ago

didn't get a warning there was an answer as i answered only a few seconds later ...

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