serviceType = ""
while serviceType != "R" or serviceType != "P":
serviceType = input("Service type (R/P): ").upper()
print(serviceType)
if serviceType != "R" or serviceType != "P":
print("Error: Invalid Entry \n")
Whenever I run the code above, the output, no matter what input I put into it, is the message "Error: Invalid Entry". Is there something I am doing wrong?
One of the conditions in your if condition is always True, therefore you always get the error.
Try this:
serviceType = ""
while serviceType != "R" and serviceType != "P":
serviceType = input("Service type (R/P): ").upper()
print(serviceType)
if serviceType not in ["R", "P"]: # <- line changed
print("Error: Invalid Entry \n")
or to and in the if statement+do the same for the while loop if you assume that you need to exit the loop when serviceType is "R" or "P"
True as your input will always be either not "R" or not "P". Thus, you are validating that neither are correct at the same time, which needs andHere's a more typical structure for this kind of pattern:
while True:
serviceType = input('Service type (R/P): ').upper()
if serviceType in ('R', 'P'):
break # serviceType is either R or P
print('Error: Invalid entry')
print(serviceType) # use the validated serviceType here
As per my understanding you want to build a program which takes service type from user and if the service type is not R or P, it return an invalid entry message and keep taking user input until user enter R or P. The following code works for me.
serviceType = ""
while serviceType != "R" and serviceType != "P":
serviceType = input("Service type (R/P): ").upper()
print(serviceType)
if serviceType != "R" and serviceType != "P":
print("Error: Invalid Entry \n")
