"Uncaught TypeError: Cannot set properties of undefined" on Javascript

Question

While trying to add new elements to the array I have, I get the error "Uncaught TypeError: Cannot set properties of undefined (setting '1')".

var arry = [[[[]]]],
    i1 = 0,
    i2 = 0,
    intervalRate = 1000;
    turn = 0, a = 10, b = 5;

for(i = 0; i < 2; i++) arry.push([]);

    setInterval(() => {
        
        
        arry[turn][i1][i2] = ([a, b]); //the error comes in this line
        i2++;
        if(i2 % 5 == 0 && i2 != 0){
            i1++;
            i2 = 0;
            arry.push([]);
        } 

        turn++;
        if(turn == 3) turn = 0;

        a += 5; b += 5;

    }, intervalRate);

How can I solve this?

arry.push([]) only adds an empty array to your arry, so when you try to access the array in that array, it doesn't exist. arry is 2 levels deep, but you're only adding 1 level with this line. — fdomn-m
– fdomn-m, Commented Aug 16, 2022 at 8:08

Nenad · Accepted Answer · 2022-08-16 09:22:25Z

1

If you run this code snippet JSFiddle:

var arry = [[[[]]]],
    i1 = 0,
    i2 = 0,
    intervalRate = 1000;
    turn = 0, a = 10, b = 5;

for(i = 0; i < 2; i++) arry.push([]);

console.log(arry);
console.log(arry[0][0]);
console.log(arry[1][0]);

Console output is:

[[[[]]], [], []] // 3 root elements
[[]] // 1st child of array[0];
undefined // 1st child of array[1]

So to fix, you would have to initialize all elements of all array dimensions, but the last one. If you use arry[turn][i1][i2], you have to cover (initialize upfront) for all possible values of turn and i1 to avoid error. Or, even better, to change the approach/algorithm completely. Find cleaner way.

answered Aug 16, 2022 at 9:22

Nenad

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