Check input in if else statement not working in python

Question

I am wondering what I'm doing wrong. I want the following if/else statement to print "The number is 4." when 4 is entered in the input. But after entering 4, it always says "Number is not 4." It is in python. Thanks in advance


if sample_number == 4:
    print("The number is 4")
else:
    print("Number is not 4.")

Most likely sample_number is the string 4 and not the number 4. Try like this: int(sample_number). — traveh
– traveh, Commented Aug 16, 2022 at 22:25

niklasbec · Accepted Answer · 2022-08-16 22:24:47Z

1

The input type is a string so 4 != "4"

This will work:

if sample_number == "4":
    print("The number is 4")
else:
    print("Number is not 4.")

answered Aug 16, 2022 at 22:24

niklasbec

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Comments

x72 · Accepted Answer · 2022-08-16 22:27:55Z

0

I dont have a lot of context but it's most likely a string so just try converting it like this:

sample_number = int(sample_number)
if sample_number == 4:
    print("The number is 4")
else:
    print("Number is not 4.")

answered Aug 16, 2022 at 22:27

x72

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