I need to parse a CSS file and change the path of an image in similar declarations to the following?
url("/images/...")
to basically change anything in between url("")
I want to replace
url('images/img.jpg'), url("images/img.jpg")
and
url(images/img.jpg)
for url(/newpath/images/img.jpg)
I need to somehow get the current path so that I can append it to the new one
You can do this:
$line = "background-image: url(/images/image.png) no-repeat;";
//or $line = "background-image: url( /images/image.png ) no-repeat;";
echo preg_replace('/(?<=url\()[^\)]+(?=\))/x', '/newfolder/newimage.png', $line);
The regexp says:
[^\)]+ string of 1 caracter or more, without )(?<=url\() before this string, there must be url((?=\)) after the string, there must be )x whitespace data characters in the pattern are totally ignored except when escaped or inside a character class (more info).
x modifier and put the explanation into the code. also you can use () for delimiters.x modifier. I don't understand what u mean by () for delimiters. Feel free to edit my answer.Use regular expressions and preg_replace. Something like:
url\(([^\)]+)\)
url(\1) as a replacement in preg_match(). \1 contains the matched string inside the url()Or you could serve your css files as php scripts via .htaccess, like this:
<FilesMatch "\.css$">
php_value default_mimetype "text/css"
SetHandler application/x-httpd-php
</FilesMatch>
And then in every css file you could defined your media path and use it wherever you want, like:
<?php define('MEDIA_PATH', '../images/'); ?>
.class{background-image:url(<?php echo MEDIA_PATH;?>background.jpg)}
