Python tkinter Entry Function not saving input into variable

Question

I am trying to use tkinter to have a user input variables to pass it into a function. The problem is , the input from the user is not being assigned to the actual variable for whatever reason.

root = Tk()
root.geometry("600x300")


MainWindow = Label(root, text = "Input var:")
MainWindow.grid(row=0, column = 0)
var= Entry(root)
var.grid(row=0, column=1)

I have about 20 variables being asked for in the GUI that has similar code to the above.

I then assign a button to display what is assigned to the variable (for troubleshooting purposes, the original purpose of the button is to pass the variables into a function).

buttonGo=Button(root, text="Generate", command= lambda: print(f'Var is : {var}'))
buttonGo.grid(row=20, column=1)
buttonExit
buttonExit.grid(row=20, column=2)    

root.mainloop()

When I run the program and click on the "Generate" button, I get the below output and not what I define it in the program.

Var is : .!entry

There's a difference between a widget and the data managed by a widget. You're printing out the widget. Are you aware of the get method? — Bryan Oakley
– Bryan Oakley, Commented Sep 25, 2022 at 22:52
I've tried using the get method by modifying the var assignment line to: "var= Entry.get(root)". I end up getting an error message saying "bad option "get": must be cget or configure". Using cget or configure gives me different error messages. — MoMo
– MoMo, Commented Sep 25, 2022 at 22:55
You have to call get on an instance of Entry, not on the class (eg: var.get() in your example) — Bryan Oakley
– Bryan Oakley, Commented Sep 25, 2022 at 22:58
Do you mind explaining a bit more? Everywhere I look I see documentation explaining how the variable should equal to the instance of Entry. You're example is the first I'm seeing like this. — MoMo
– MoMo, Commented Sep 25, 2022 at 23:13

paxdiablo · Accepted Answer · 2022-09-25 23:22:40Z

2

That .!entry is the widget, not the value. If you want the value, you need to use the get() method of the widget.

In other words, something like:

value = var.get()
# Now use value.

edited Sep 25, 2022 at 23:22

answered Sep 25, 2022 at 23:11

paxdiablo

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7 Comments

MoMo Over a year ago

I've tried using the get method by modifying the var assignment line to: "var= Entry.get(root)". I end up getting an error message saying "bad option "get": must be cget or configure". Using cget or configure gives me different error messages. What am I doing wrong?

Tim Roberts Over a year ago

No, no, no. You need var to be the widget: var = Entry(root). When you want the value stored in the widget, you'll use var.get().

MoMo Over a year ago

I added a 'var.get()' line right below the 'var = Entry(root)' and I get the same output of 'Var is : .!entry'. Not sure what I'm missing. @paxdiablo, also replying to the comment you just posted.

paxdiablo Over a year ago

@MoMo, that change tries to call the class get() method which does not exist. As Tim states, var = Entry(...) is correct but you need var.get() to get the value.

paxdiablo Over a year ago

@MoMo, var.get() on its own will get the value and throw it away. You need to do something like value = var.get() then use value. Updated the code to make that clearer.

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MoMo · Accepted Answer · 2022-09-25 23:50:50Z

0

Based on the replies I got, I believe I found the answer to be using .get method when calling the function. I modified the line to:

buttonGo=Button(root, text="Generate", command= lambda: print(f'Var is : {var.get()}'))

Thanks for the replies and explanations.

answered Sep 25, 2022 at 23:50

MoMo

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