Iterating through attributes using xslt

Question

I have an xml data which has shown below.

<Roll NO="4620" CLASSNO="0" ID="0" DID="0" REVSN="0" DNO="3" ></Roll>
<Roll NO="4630" CLASSNO="0" ID="0" DID="0" REVSN="0" DNO="3"></Roll>

I want to iterate through the attributes without specifying the name using XSLT. Any way to do it?

While this can be done, bear in mind that the order of attributes is undefined and different XSLT processors can traverse and output the results of processing each attribute in different order. This means that the output is unpredictable, implementation-dependent and any solution that "iterates" through attributes isn't portable. One solution to this problem is to use <xsl:sort> and process the attributes sorted by name. This would be portable. On the other hand, it may not be possible with all XSLT processors to process the attributes in their "visible order". — Dimitre Novatchev
– Dimitre Novatchev, Commented Sep 13, 2011 at 4:35
@Dimitre: That's only a problem if the order is important in the output; this isn't specified in the question. Just out of curiosity, do you know of ANY xslt processor that doesn't process them in the 'visible order'? I've yet to find one that doesn't. — Flynn1179
– Flynn1179, Commented Sep 13, 2011 at 6:49
@Flynn1179: I think that the order isn't determined by the XSLT processor at all, but by the XML parser that uses. I haven't made any investigations in what order different XML parsers present attributes, but wouldn't (shouldn't) be surprized if some XML parsers produce them not in the "visible" order -- as this is not mandated by the XML specification. Here is an example -- a default attribute from a DTD/Schema that isn't "visible" in the text of the XML document. At which position in the "ordered" sequence of attributes should the default attribute be? A parser may decide as it likes! — Dimitre Novatchev
– Dimitre Novatchev, Commented Sep 13, 2011 at 12:15

Kirill Polishchuk · Accepted Answer · 2011-09-12 12:20:39Z

17

You can use this XPath @* to get all attributes, e.g.:

XML:

<Roll NO="4620" CLASSNO="0" ID="0" DID="0" REVSN="0" DNO="3"/>

XSLT:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="/*">
        <xsl:for-each select="@*">
            <xsl:value-of select="concat(name(), ': ', ., ' ')"/>
        </xsl:for-each>
    </xsl:template>

</xsl:stylesheet>

Output:

NO: 4620 CLASSNO: 0 ID: 0 DID: 0 REVSN: 0 DNO: 3

answered Sep 12, 2011 at 12:20

Kirill Polishchuk

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Christopher Creutzig · Accepted Answer · 2011-09-12 12:18:15Z

1

Your code is not well-formed xml, but as for the question surrounding it:

<xsl:template match="Roll"> <!-- or "SB" or whatever -->
  <xsl:for-each select="@*">
    <!-- ... whatever you want to do with them ... -->
    <!-- use local-name and value(.) -->
  </xsl:for-each>
</xsl:template>

answered Sep 12, 2011 at 12:18

Christopher Creutzig

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