Manipulate array filter in php value array not change [duplicate]

Question

I have array an array with this value

array:11 [
 "id" => 4
  "title" => "CLUSTER AIRING"
  "channel_title" => "CLUSTER AIRING"
  "parent_id" => 2
  "start_date" => "2022-09-30 10:59:00"
  "end_date" => "2022-09-30 13:58:00"
  "image_url" => "https://stag-sections-image.visionplus.id/media/"
  "content_core_id" => 2
  "type" => "Channel"
  "content_type" => "Channel"
  "is_upcoming" => true
]

I already make this code to filter start_date & end_date this filter already works. but when I changed the valueis_upcoming from true to it's not changed. but when I make dd() to $item this is already changed to false. Here is my code

$data = array_values(array_filter($data, function($item){
       if (($item['start_date']) <= now() && ($item['end_date'] >= now()) ) {
               $item['is_upcoming'] = false;
               return $item;
       }
       if ($item['start_date'] > now()) {
               $item['is_upcoming'] = true;
               return $item;
           }
}));

JS TECH · Accepted Answer · 2022-09-30 05:12:56Z

0

The callback is used to return a boolean value to determine whether to include or exclude the object/value in array_filter. But you're using it to return the entire data which makes the callback always return true. Use array_map() instead of array_filter().

$data = array_map(function($item){
    if (($item['start_date']) <= now() && ($item['end_date'] >= now()) ) {
        $item['is_upcoming'] = false;
        return $item;
    }
    if ($item['start_date'] > now()) {
        $item['is_upcoming'] = true;
        return $item;
    }
}, $data);

answered Sep 30, 2022 at 5:12

JS TECH

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