regex to get multiple values in javascript

Question

my string is

Cuenta de Ahorros | 1231231231 Bs 102,423.88 Cuenta de Ahorros | 1231233123 Usd 102,423.88 Cuenta de Ahorros | 87316633 Usd 10.233 Cuenta de Ahorros | 49189387113313 Usd 12.301

but using match() i can't capture all string values

const strings = [
  "Cuenta de Ahorros | 1231231231 Bs 102,423.88 Cuenta de Ahorros | 1231233123 Usd 102,423.88 Cuenta de Ahorros | 87316633 Usd 10.233 Cuenta de Ahorros | 49189387113313 Usd 12.301"
]; 

let pattern = /(?<=Bs).*?(?=Cuenta)/;
strings.forEach((s) => {
  console.log(s.match(pattern));
});

returns only

[" 102,423.88 ", 40, "Cuenta de Ahor...] 0 : " 102,423.88 "

i need result like

Bs 102,423.88

Usd 102,423.88

Usd 10.233

Usd 12.301

There seems to be many things going on here: If you need Bs in the output, and Usd, too, you need a group: (Bs|Usd). If you need it in the match, why use lookbehind? Use a consuming pattern. To extract multiple matches, use g flag in the regex with String#match — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Oct 2, 2022 at 19:32

The fourth bird · Accepted Answer · 2022-10-02 20:32:57Z

As you also want to match the dollar variant, you could write the pattern including matching Bs and Usd as:

\b(?:Bs|Usd)\s+(?:\d{1,3}(?:,\d{3})*(?:\.\d+)?|\d{4,})(?=\s+Cuenta\b|$)

Explanation

\b A word boundary to prevent a partial word match
(?:Bs|Usd)
\s+ Match 1= whitespace chars
(?: Non capture
- \d{1,3} Match 1-3 digits
- (?:,\d{3})* Optionally repeat , and 3 digits
- (?:\.\d+)? Optionally match . and 1 + digits
- | Or
- \d{4,} Match 4 or more digits
) Close non capture group
(?=\s+Cuenta\b|$) Assert either 1+ whitespace chars and Cuenta to the right or assert the end of the string

Regex demo

const pattern = /\b(?:Bs|Usd)\s+(?:\d+(?:,\d{3})*(?:\.\d+)?|\d{4,})(?=\s+Cuenta\b|$)/g;
const strings = [
  "Cuenta de Ahorros | 1231231231 Bs 102,423.88 Cuenta de Ahorros | 1231233123 Usd 102,423.88 Cuenta de Ahorros | 87316633 Usd 10.233 Cuenta de Ahorros | 49189387113313 Usd 12.301"
];

strings.forEach((s) => {
  console.log(s.match(pattern));
});

Or using matchAll with a capture group:

const pattern = /(\b(?:Bs|Usd)\s+(?:\d{1,3}(?:,\d{3})*(?:\.\d+)?|\d{4,}))(?:\s+Cuenta\b|$)/g;
const strings = [
  "Cuenta de Ahorros | 1231231231 Bs 102,423.88 Cuenta de Ahorros | 1231233123 Usd 102,423.88 Cuenta de Ahorros | 87316633 Usd 10.233 Cuenta de Ahorros | 49189387113313 Usd 12.301"
];

strings.forEach((s) => {
  console.log(Array.from(s.matchAll(pattern), m => m[1]));
});

Wiktor Stribiżew · Accepted Answer · 2022-10-02 19:34:12Z

You can use

const strings = [
  "Cuenta de Ahorros | 1231231231 Bs 102,423.88 Cuenta de Ahorros | 1231233123 Usd 102,423.88 Cuenta de Ahorros | 87316633 Usd 10.233 Cuenta de Ahorros | 49189387113313 Usd 12.301"
]; 

let pattern = /\b(?:Bs|Usd)\b.*?(?=\s*Cuenta\b|$)/gi;
strings.forEach((s) => {
  console.log(s.match(pattern));
});

See the regex demo.

Pattern details:

\b(?:Bs|Usd)\b - a whole word Bs or Usd
.*? - any zero or more chars other than line break chars, as few as possible
(?=\s*Cuenta\b|$) - a positive lookahead that requires (immediately to the right of the current location) either zero or more whitespaces and then a whole word Cuenta (\s*Cuenta\b|$), or end of string ($).

I added g flag and used String#match to extract all matches from a string, and i flag makes the search case-insensitive.

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