How to remove initial dot from a string in a variable in bash

Question

I have a variable named myVar in bash with value as shown below.

'./favicon.png' './inc/sendEmail.php' './index.html' './images/header-background.jpg'

Note: the above code is the value of one variable

And I want want to change it to the below string by removing initial dot from each path

'/favicon.png' '/inc/sendEmail.php' '/index.html' '/images/header-background.jpg'

I am not able to figure out how to do this. Please help.

That's possible, for example using sed "s/'\./'/g" <<< "$string", but if you have any control over whatever generates the string, you should fix it where it's created, and also use an array instead of a string with hardcoded quotes, as any further processing tends to be more difficult with what you have. — Benjamin W.
– Benjamin W., Commented Oct 9, 2022 at 15:11

Fravadona · Accepted Answer · 2022-10-09 15:16:21Z

2

With a bash parameter expansion?

#!/bin/bash

myVar="'./favicon.png' './inc/sendEmail.php' './index.html' './images/header-background.jpg'"

echo "${myVar//.\///}"

'/favicon.png' '/inc/sendEmail.php' '/index.html' '/images/header-background.jpg'

answered Oct 9, 2022 at 15:16

Fravadona

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