I'm trying to create a regex that will matches with
"8-9."
but won't matches with
"8-9........"
I tried lots of possibilities yet, but still can't find the right one.
-
3Please show what you have tried and how it fails.Chris Dunaway– Chris Dunaway2011-09-13 13:55:51 +00:00Commented Sep 13, 2011 at 13:55
-
To be clear: you want to match exactly the characters "8-9." (eight dash nine dot) and that's not a regex pattern, yes? Or do you want to match all digits between 8 and 9 followed by any character?Tremmors– Tremmors2011-09-13 13:57:10 +00:00Commented Sep 13, 2011 at 13:57
-
What is the string you want to match? What do you not want to match? how does the pattern look that you have tried? ... You need to be a lot more specific.stema– stema2011-09-13 13:57:21 +00:00Commented Sep 13, 2011 at 13:57
Add a comment
|
2 Answers
Without a better worded question, ^8-9$ should do it..
Comments
try
Dim r As Regex = New Regex("8\-9")
'Look for match
Dim m As Match = r.Match(mystring)
also might use
Dim r As Regex = New Regex("^8\-9$")
if you want a single word
4 Comments
Alan Moore
- has no special meaning unless it's used inside a character class (e.g. [a-z]).
Konrad Rudolph
In VB,
x As Y = new Y… should always be replaced by x As New Y….
Blindy
@Konrad, is that VB's equivalent of
var? I've always wondered.Konrad Rudolph
@Blindy No. VB’s equivalent of
var is Dim without a data type, when Option Infer is enabled. So just Dim x = "Hello". However, due to the above-mentioned syntax shortcut, this is less often necessary than var in C#.