If I have a nested dictionary and varying lists:
d = {'a': {'b': {'c': {'d': 0}}}}
list1 = ['a', 'b']
list2 = ['a', 'b', 'c']
list3 = ['a', 'b', 'c', 'd']
How can I access dictionary values like so:
>>> d[list1]
{'c': {'d': 0}}
>>> d[list3]
0
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1while not a strict duplicate, this is a close match: stackoverflow.com/q/31033549/758174Pierre D– Pierre D2022-10-12 20:14:10 +00:00Commented Oct 12, 2022 at 20:14
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good point, couldn't find that googling!Oliver– Oliver2022-10-12 21:06:53 +00:00Commented Oct 12, 2022 at 21:06
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2 Answers
you can use functools reduce. info here. You have a nice post on reduce in real python
from functools import reduce
reduce(dict.get, list3, d)
>>> 0
EDIT: mix of list and dictioanries
in case of having mixed list and dictionary values the following is possible
d = {'a': [{'b0': {'c': 1}}, {'b1': {'c': 1}}]}
list1 = ['a', 1, 'b1', 'c']
fun = lambda element, indexer: element[indexer]
reduce(fun, list1, d)
>>> 1
5 Comments
Oliver
This is a great answer. But I realize it doesn't work if you have lists in your dictionary like so
d = {'a': [{'b0': {'c': 1}}, {'b1': {'c': 1}}]} and a list like so ['a', 1, 'c']
Lucas M. Uriarte
It is possible let me make an edit
Lucas M. Uriarte
actually is possible if your list is as follow ['a', 1, 'b1' 'c'], would that pass? In any case I have added an edit
Oliver
legendary .....
Lucas M. Uriarte
you can check the real python post whenever you have time, is quite nice, reduce can be very useful!
Use a short function:
def nested_get(d, lst):
out = d
for x in lst:
out = out[x]
return out
nested_get(d, list1)
# {'c': {'d': 0}}
