Python if ... else on one line

Question

So im trying to get 2 lists with the infected and detected. results (almost always) contains False and could contain True. im getting a keyerror with this code. Maybe a try..catch but what if either infection or detection is empty?

results = {'infected': {False: 39}, 'detection': {False: 39}}
    
infectedDetected = [results['infected'][True],
                    results['detection'][True]]

notinfectedDetected = [results['infected'][False],
                       results['detection'][False]]

Example of the preferred output:

infectedDetected = [0, 0]
notinfectedDetected = [39, 39]

What i've tried:

infectedDetected = [results['infected'][True] if not Keyerror else 0,
                    results['detection'][True] if results['detection'][True] != KeyError else 0]

notinfectedDetected = [results['infected'][False],
                       results['detection'][False]]

Does this answer your question? Does Python have a ternary conditional operator? — YUVI_1303
– YUVI_1303, Commented Oct 17, 2022 at 11:13
@YUVI_1303 kind of but how do i deal with the key error? thats why i was thinking of a try and catch but how does that account for if one of them is not filled? — f33lthepkfromprins
– f33lthepkfromprins, Commented Oct 17, 2022 at 11:16
Does this answer your question? Check if a given key already exists in a dictionary — Luuk
– Luuk, Commented Oct 17, 2022 at 11:27

Anis R. · Accepted Answer · 2022-10-17 11:18:31Z

1

To solve the KeyError, you can check if the dict contains the desired key like so:

if True in results['infected']

So the ternary operator in your case can look like:

infectedDetected = [results['infected'][True] if True in results['infected'] else 0,
                results['detection'][True] if True in results['detection'] else 0]

answered Oct 17, 2022 at 11:18

Anis R.

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Peter · Accepted Answer · 2022-10-17 11:18:54Z

1

I presume you can manage with try/except KeyError, but this is an alternative way where you can use the default value of .get().

infectedDetected = [results.get('infected', {}).get(True, 0),
                    results.get('detection', {}).get(True, 0)]

notinfectedDetected = [results.get('infected', {}).get(False, 0),
                       results.get('detection', {}).get(False, 0)]

answered Oct 17, 2022 at 11:18

Peter

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