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values = ['random word1', 20, 'random word2', 54…]

The list has a string then a value and again a string then afterwards a value. The amount of strings followed by values is random. The words are random and the values are random as well

I want to convert the list to something like this:

values = [['random word1', 20], ['random word2', 54]…]
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4 Answers 4

Reset to default
2 
values = ['random word1', 20, 'random word2', 54]
values = [values[i:i+2] for i in range(0,len(values),2)]
print(values)
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1 Comment

I have tried this method as well it works. Thanks.
2

Try this:

values = ['random word1', 20, 'random word2', 54]
print([list(x) for x in zip(values[::2], values[1::2])])
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1 Comment

I have tried this method as well it works. Thanks.
0

You can do it with zip and list slicing.

list(map(list,zip(values[::2], values[1::2])))
# [['random word1', 20], ['random word2', 54]]
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4 Comments

list(map(list,zip( ... I suppose it's too much for the beginning beginner to understand what will be going on without a page or two of explanations ...
I have tried this method as well it works. I will choose this one as best because there is no for loop involved. I guess if the list had thousands of strings and values this would run faster than the other answers correct?
@ETHERC20, I think this method does for loops. Functions like map() and zip() create an iterator, so you need to do a for loop if you want to process all the elements, this is what list() function does.
@Mayo in this case what would you suggest? If the list had tens of thousands of strings and values it will run slow correct? How can I make it better?
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b = [[values[i], values[i+1]] for i in range(len(values)) if i%2==0]
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2 Comments

First think, than write code and finally test the code before posting anything here on stackoverflow.
It's actually what' i've done, but with a very specific (and wrong) test case. There is no need to be rude.

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