PHP: send array as form post input parameter [duplicate]

Question

I have a pre-defined $dogs array. I'd like to send it with an HTML form:

<?php

$dogs = array("A", "B", "C");

?>

<form action="tester.php" method="post">
    <input type="text" name="text">
    <input name="dogs[]" style="display: none">

    <input type="submit"/>
</form>

 <?php
 $textValue = '';
 if (sizeof($_POST) != 0) {
     try {
         $textValue = $_POST['text'];
         print_r($dogs);
         print_r('after...');

         $cats = $_POST('dogs');
         print_r($cats);
     } catch (Exception $exception)  {
        print_r($exception);
     }
 }

?>

<div>Value: <?php  echo $textValue ?></div>

The form submits to the same page.

I get the output:

Array ( [0] => A [1] => B [2] => C ) after...

If I comment out the last two lines in the try statement:

         $textValue = $_POST['text'];
         print_r($dogs);
         print_r('after...');

         // $cats = $_POST('dogs');
         // print_r($cats);

I get:

Array ( [0] => A [1] => B [2] => C ) after...
Value: myvalue

I'd like to get output:

Array ( [0] => A [1] => B [2] => C ) after...Array ( [0] => A [1] => B [2] => C )
Value: myvalue

How should I change the code to get it?

EDIT:

I changed the code to

<?php

$dogs = array("A", "B", "C");

?>

<form action="tester.php" method="post">
    <input type="text" name="text">
    <input name="dogs[]" style="display: none">

    <input type="submit"/>
</form>

 <?php
 $textValue = '';
 if (sizeof($_POST) != 0) {
     try {
         $textValue = $_POST['text'];
         print_r($dogs);
         print_r('after...');

         $cats = $_POST['dogs'];
         print_r($cats);
     } catch (Exception $exception)  {
        print_r($exception);
     }
 }

?>

<div>Value: <?php  echo $textValue ?></div>

now I get this output:

Array ( [0] => A [1] => B [2] => C ) after...Array ( [0] => )
Value: myvalue

it's a typo $_POST('dogs'); should be square braces to access values in POST — Kevin
– Kevin, Commented Oct 24, 2022 at 4:25
@Kevin I changed it to ` $cats = $_POST('dogs[]');` and get the same result — parsecer
– parsecer, Commented Oct 24, 2022 at 5:22
@Cositanto I tried $_POST['dogs'] - it's the original code in my post — parsecer
– parsecer, Commented Oct 24, 2022 at 5:29

Cositanto · Accepted Answer · 2022-10-24 05:39:36Z

1

If you want to send the $dogs in your form, you can try:

<form action="tester.php" method="post">
<input type="text" name="text">
<?php
    foreach ($dogs as $dog) {
?>
    <input name="dogs[]" value="<?php echo $dog; ?>" style="display: none">
<?php
    }
?>
<input type="submit"/>

answered Oct 24, 2022 at 5:39

Cositanto

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2 Comments

parsecer Over a year ago

What if $dogs is an array of arrays? A 2D array?

Cositanto Over a year ago

Maybe json is easier, like <input name="dogs" value='<?php echo json_encode($dogs); ?>' >, and use json_decode($_POST['dogs']) to receive it after form post.

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