Wrong indexing of a string (Python)

Question

Something that should be very simple and yet I am not able to solve it. The indexing does not appear correctly when a character duplicates: For example:

list=[]
stringg="BAtmAn"
for i in stringg:
    if i.isupper():
        list.append(stringg.index(i))
print(list)

And the output shows [0,1,1] instead of [0,1,4]. When the stringg variable is changed to "BAtmEn" it appears the way I expect it to appear in the first example.

index returns the index of the first match unless you provide a start. — 001
– 001, Commented Oct 25, 2022 at 12:32
Try using enumerate instead. Example for index,letter in enumerate(stringg): if letter.isupper(): lst.append(index) — 001
– 001, Commented Oct 25, 2022 at 12:36
Note: don't use list as a variable name as it will conflict with the built in list class. — 001
– 001, Commented Oct 25, 2022 at 12:37

LinFelix · Accepted Answer · 2022-10-25 12:35:41Z

1

The following would do what you want

stringg="BAtmAn"
print([x for x in range(len(stringg)) if stringg[x].isupper()])
print([i for i, c in enumerate(stringg) if c.isupper()])

answered Oct 25, 2022 at 12:35

LinFelix

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hadi yousefi · Accepted Answer · 2022-10-25 12:50:47Z

0

list=[]
stringg="BAtmAn"
for i in range(len(stringg)):
    if stringg[i].isupper():
        list.append(i)
print(list)

should try this... .index('item') can only find the index of the first of that 'item' in the list.

answered Oct 25, 2022 at 12:50

hadi yousefi

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