jQuery - Finding Distinct Values in Object Array

Question

I've got an array of objects where each object has fields like title, description, family, etc. How can I perform a jQuery operation that grabs all objects in this array with a unique family name - similar to SQL's DISTINCT clause?

I think this has been answered before stackoverflow.com/questions/1960473/unique-values-in-an-array — Drake
– Drake, Commented Sep 15, 2011 at 13:28
@Drake - I was hoping to find a jQuery solution if possible, but thank you I did not see that link the in stackoverflow recommendations — Dexter
– Dexter, Commented Sep 15, 2011 at 13:32
@bstakes - nothing that's working obviously. I was using grep to grab elements where I had specific matches but I don't have a specific value I'm grabbing in this case. I also reviewed using data as an option, but again, this requires a value to match against. — Dexter
– Dexter, Commented Sep 15, 2011 at 13:35

Nicola Peluchetti · Accepted Answer · 2012-07-07 12:40:05Z

21

You could do:

var array = [{
    familyName: "one"},
{
    familyName: "two"},
{
    familyName: "one"},
{
    familyName: "two"}];

var dupes = {};
var singles = [];

$.each(array, function(i, el) {

    if (!dupes[el.familyName]) {
        dupes[el.familyName] = true;
        singles.push(el);
    }
});

Singles is an array with only DISTINCT objects

EDIT - i have blogged about this and given a more elaborate answer http://newcodeandroll.blogspot.it/2012/01/how-to-find-duplicates-in-array-in.html

edited Jul 7, 2012 at 12:40

answered Sep 15, 2011 at 13:33

Nicola Peluchetti

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