python automatically create parameters in a lambda function

Question

constraint_condition = [lambda x: [x[0], x[1]]]
mid.gen_answer(constraint_ueq)

In codes above, mid is a class, and the method gen_answer is calling a function from another python package which requires n-dimension input written in this format： lambda x:[x[0],x[1],...x[n]]

How do I create lambda function and fill these paramters automatically? For example I want a 4-dimension input, I shall be writing this by my hand like this: lambda x:[x[0],x[1],x[2],x[3]], but what if there are more dimensions(like 12)? There is a way to let python write these (x[1],x[2]...) for me?

to add to @jfaccioni one liner, if you want less indexes than whole length of x, you can do in x[:k] where k is the number of dims. — matszwecja
– matszwecja, Commented Nov 4, 2022 at 14:58

Austie Chou · Accepted Answer · 2023-03-25 14:43:06Z

1

Guy, I solved this by using lambda x:[sub_x for sub_x in x[:n]]. Thx for your help

edited Mar 25, 2023 at 14:43

answered Nov 12, 2022 at 10:47

Austie Chou

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