How to get XML value in Python

Question

I'm trying to read XML value from the soap response. Included the response below, I'm trying to read the Bearer token from the below XML. Tried a couple of ways but failed.

<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
    <ofo:GetToken xmlns:ofo="http://dummyurl.com/xsd/xyz">
        <ofo:Token>Bearer 123sfafweo123</ofo:Token>
    </ofo:GetToken>
</soapenv:Body>
</soapenv:Envelope>

Code I tried

  import import lxml.etree
 
  # send request to get above response.
  response = requests.post(url, data=body, headers=headers)
  root = lxml.etree.fromstring(response.content)
  textelem = root.find('Envelope/Body/GetToken/Token')
  print(textelem)

@user29496 Please edit your question and add this attempt there, not in a comment. — Jack Fleeting
– Jack Fleeting, Commented Nov 13, 2022 at 14:52

Jack Fleeting · Accepted Answer · 2022-11-13 17:19:18Z

1

Your original code failed to take into account namespaces. There are a couple of way to approach it. This, for example, should work

ns = {"ofo": "http://dummyurl.com/xsd/xyz"}
root.xpath('//ofo:Token/text()',namespaces=ns)[0]

or, if you want to avoid dealing with namespaces:

doc.xpath('//*[local-name()="Token"]/text()')[0]

Output, in either case:

Bearer 123sfafweo123

answered Nov 13, 2022 at 17:19

Jack Fleeting

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2 Comments

user29496 Over a year ago

Thanks a lot. I was able to retrieve the code

Jack Fleeting Over a year ago

@user29496 Glad it worked for you!

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