Golang Split String with Regexp

Question

I have a string and I split the string with regexp package. However I could not create a regexp I need.

The regexp code lines:

v = "@636e0e0eac0bd25cd5df92a3$636e0e49ac0bd25cd5df92a5.result.result[0].code.xTrim()"
r, _ := regexp.Compile(`(@[a-zA-Z0-9]+\$[a-zA-Z0-9]+)(.*)`)
variableParts := r.FindStringSubmatch(v)

VariablesParts array:

0: "@636e0e0eac0bd25cd5df92a3$636e0e49ac0bd25cd5df92a5.result.result[0].code.xTrim()"

1: "@636e0e0eac0bd25cd5df92a3$636e0e49ac0bd25cd5df92a5"

2: ".result.result[0].code.xTrim()"

This is my desired result:

Array length can change but array should include this 4 strings.

0: "@636e0e0eac0bd25cd5df92a3$636e0e49ac0bd25cd5df92a5.result.result[0].code.xTrim()"

1: "@636e0e0eac0bd25cd5df92a3$636e0e49ac0bd25cd5df92a5"

2: ".result.result[0].code.xTrim()"

3: ".xTrim()"

How Can I get this result. Which regexp string I need?

UPDATE for new desired result:

1: "@636e0e0eac0bd25cd5df92a3$636e0e49ac0bd25cd5df92a5"

2: ".result.result[0].code.xTrim()"

3: ".result"

4: ".result[0]"

5: ".code"

6: ".xTrim()"

Why are you using regex? strings.Split would be a lot simpler (and faster) — Jonathan Hall
– Jonathan Hall, Commented Nov 15, 2022 at 10:52
As for the problem with your regex: You probably mean \.(.*) at the end. — Jonathan Hall
– Jonathan Hall, Commented Nov 15, 2022 at 10:53

Wiktor Stribiżew · Accepted Answer · 2022-11-15 10:54:28Z

1

You can replace the last (.*) part with (.*(\.[^.]*))$ and use

(@[a-zA-Z0-9]+\$[a-zA-Z0-9]+)(.*(\.[^.]*))$

See the regex demo. Details:

(@[a-zA-Z0-9]+\$[a-zA-Z0-9]+) - Group 1: a @ char, then one or more alphanumeric chars, then a # char and then again one or more alphanumeric chars
(.*(\.[^.]*)) - Group 2: any zero or more chars other than line break chars as many as possible, and then Group 3: a ., zero or more chars other than a . char
$ - at the end of string. Remove if there can be more text on the right.

answered Nov 15, 2022 at 10:54

Wiktor Stribiżew

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4 Comments

oakkose Over a year ago

It worked, also I edited question for new desired result. How should I change regexp string to get the new result?

Wiktor Stribiżew Over a year ago

@oakkose Split with ., e.g. strings.Split(text,`.`). Or match with [^.]+ regex, e.g. here

oakkose Over a year ago

I updated desired result again. With strings.Split I can not get the result. How should regex string be?

Wiktor Stribiżew Over a year ago

@oakkose You can only use regex for this if you know the maximum number of substrings you want to capture. Then just add the optional groups, see regex101.com/r/q3svdX/3

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