I have a string query
const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight';
I want to store the words inside "NOT" block in an array. What could be the most effective approach for this?
Expected result - ["app", "agency"]
We can use match(), twice:
const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight';
var terms = query.match(/\bNOT\s*\((.*?)\)/)[1]
.match(/\w+/g)
.filter(x => x !== "OR" && x !== "AND");
console.log(terms);
const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight';
function useRegex(input) {
let regex = /\(([a-zA-Z]+( [a-zA-Z]+)+)\) NOT \(([a-zA-Z]+( [a-zA-Z]+)+)\) ([A-Za-z0-9]+( [A-Za-z0-9]+)+)/i;
return input.match(regex);
}
console.log(useRegex(query)[3]);Step 1: Split the query before and after NOT keyword using query.split('NOT')
-> Here only data after NOT is needed so we can use, query.split('NOT')[1]
Step 2: Use regex rx.exec(res)[1] to get the value in between the paranthesis.
Step 3: Get the values before and after OR.
const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight';
const res = query.split('NOT')[1];
const rx = /\(([^)]+)\)/;
const result = rx.exec(res)[1].split(' OR ');
console.log(result);
