I need to instantiate an object using iterable with multiple objects inside. I have to create another method to do it
class MyClass:
def __init__(self, *args):
self.args = args
def instantiate_from_iterable
#some clever code
I need to have a result like this
MyClass.instantiate_from_iterable([1, 5, 3]) == MyClass(1, 5, 3)
MyClass.instantiate_from_iterable((3, 1, 7)) == MyClass(3, 1, 7)
I have no idea how to do this. If someone could help, I would appreciate it very much!
classmethod is what what you're after:
from collections.abc import Iterable
class MyClass:
def __init__(self, *args):
self.args = args
@classmethod
def instantiate_from_iterable(cls, args: Iterable):
return cls(*args)
a = MyClass(1, 5, 7)
b = MyClass.instantiate_from_iterable([1, 5, 7])
print(a.args) # -> (1, 5, 7)
print(b.args) # -> (1, 5, 7)
Iterable is a generic, so it should have a type parameter, shouldn't it? I think Iterable[object] would be appropriate.I am not sure what you would like to do.
Try the following:
class MyClass:
def __init__(self, *args):
self.args = args
def __eq__(self, other):
if not isinstance(other, MyClass):
return False
else:
return self.args == other.args
assert MyClass(1, 5, 3) == MyClass(*[1, 5, 3])
There would be no need for a clever function. Just unpack the list with the * before the list or tuple.
You would make the object comparably using the magic function __eq__ to make them comparable.
MyClass.__eq__()is undefined, so I'm assuming it'd be implemented asself.args == other.args). For more tips, check out How to ask a good question.