[4, 3, 2, 6] , N = 4
this is my input and I want to get the list and 4 and store all in a and b (a for the list and b for the integer)
a = list(map(int, input().strip(' []').split(',')))
i know how to get the list but I dont know how to get n because of the comma "," after and "N =" .
Use a regex, remove all non-digit/non-comma, then split on comma
value = "[4, 3, 2, 6] , N = 4"
*a, b = list(map(int, re.sub(r'[^\d,]', '', value).split(',')))
print(a) # [4, 3, 2, 6]
print(b) # 4
Here are the steps
re.sub(r'[^\d,]', '', value) # '4,3,2,6,4'
re.sub(r'[^\d,]', '', value).split(',') # ['4', '3', '2', '6', '4']
list(map(int, re.sub(r'[^\d,]', '', value).split(','))) # [4, 3, 2, 6, 4]
Then using packing you can save all the first ones in a variable, and the last one in another
Assuming the input format is exactly as shown in the question then:
import re
text = '[4, 3, 2, 6] , N = 4'
*a, b = map(int, re.findall(r'(\d+)', text))
print(a)
print(b)
Output:
[4, 3, 2, 6]
4
Using join() method Algorithm (Steps) Following are the Algorithm/steps to be followed to perform the desired task −
Create a list and add some dummy strings to it.
Get the comma-separated string from the list by passing the list as an argument to the join() function(join() is a string function in Python that is used to join elements of a sequence that are separated by a string separator. This function connects sequence elements to form a string) and create a variable to store it.
Here we pass delimiter as ‘,’ to separate the strings with comma(‘,)
Print the result of a comma-separated string.
One option:
import re
from ast import literal_eval
inpt = input('list, then assignment: ')
lst, var = re.split(r'(?<=])\s*,\s*', inpt)
lst = literal_eval(lst)
# [4, 3, 2, 6]
key, val = re.split(r'\s*=\s*', var)
var = {key: literal_eval(val)}
# {'N': '4'}
print(lst, var)
Output:
list, then assignment: [4, 3, 2, 6] , N = 4
[4, 3, 2, 6] {'N': 4}
Other example:
list, then assignment: ['a', 'b', None] , Y = 'abc'
['a', 'b', None] {'Y': 'abc'}
