How to send a variable from Laravel Controller to a Python script?

Question

$client = new Client();
$a = 'https://scholar.google.com/citations?user=';
$gscID = 'EnegzCwAAAAJ';//for eg
$b = '&hl=en&oi=ao';
$url = $a . $gscID . $b;

$crawler = $client->request('GET', $url);

//python script
$process = new Process(['python', public_path() . '\ext.py'], null, ['SYSTEMROOT' => getenv('SYSTEMROOT'), 'PATH' => getenv("PATH")]);
$process->run();

// executes after the command finishes
if (!$process->isSuccessful()) {
    throw new ProcessFailedException($process);
}
$out[] = $process->getOutput();
dd($out);

Extracting the tables from the given url webpage

Now I want to pass the $url variable to the python script stored in my public folder because everytime my url changes with different person's ID.

Any help would be really appreciated

Ana Fernandes · Accepted Answer · 2022-12-08 09:35:13Z

3

Found out an easy solution $output = shell_exec("python ext.py $url");//ext.py is name of my script and $url is my variable which I want to pass

And then in python script write

import sys
url = sys.argv[1]

answered Dec 8, 2022 at 9:35

Ana Fernandes

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Zoltan Rakottyai · Accepted Answer · 2024-12-18 17:57:59Z

Laravel's documentation recommends the use of env method mentioned here. I had to use a bash script to activate the python environment first (2nd step)

First call the process in the job controller with the env method where you can pass all your variables as an array.

$scriptPath = base_path('python/run.sh');

$process = Process::env([
  'APP_URL' => config('app.url'),
  'OUTPUT_FILE' => $outputFile,
])->run('sh ' . $scriptPath);

In the python/run.sh file I

#!/bin/bash

# Navigate to the script's directory
cd "${0%/*}"

# Activate the virtual environment
source venv/bin/activate

# Run the Python script with the output file argument
python export.py --output_file "$OUTPUT_FILE" --app_url "$APP_URL"

# Deactivate the virtual environment
deactivate

The export.py parses the arguments with the help of argparse library

import argparse

if __name__ == "__main__":
    # Save the file to the path provided as an argument

    parser = argparse.ArgumentParser(description='Export products to Excel.')
    parser.add_argument('--output_file', type=str, required=True, help='The output file path')
    parser.add_argument('--app_url', type=str, required=True, help='The application URL')

    args = parser.parse_args()

    export_products_to_excel(output_file=args.output_file,app_url=args.app_url)

Taron · Accepted Answer · 2022-12-08 09:22:41Z

0

You can add script parameters in the array that you are passing to Process. Here is the doc.https://symfony.com/doc/current/components/process.html#using-features-from-the-os-shell

answered Dec 8, 2022 at 9:22

Taron

762 bronze badges

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