Decode JSON into Symfony entity

Question

Does anyone know if there is an easy way, aside from writing a custom script to decode a JSON object into a PHP entity?

I'm using the script below to encode to JSON, but when I decode it's an array and not an entity.

$serializer = new Serializer(array(new GetSetMethodNormalizer()), array('json' => new 
            JsonEncoder()));
            $json = $serializer->serialize($coupon, 'json');
            $session->set('json', $json);

Then I'm decoding in this manner

$session = $this->getRequest()->getSession();
    $json = $session->get('json');
    $serializer = new Serializer(array(new GetSetMethodNormalizer()), array('json' => new JsonEncoder()));
    $coupon = $serializer->decode($json, 'json');

But like I said... it's no longer a Coupon entity, it's just an array.

decode will always return an array, you need to denormalize the data then which will turn it into a class. — hakre
– hakre, Commented Sep 20, 2011 at 10:29

hakre · Accepted Answer · 2011-09-20 10:31:19Z

9

Assuming the following works:

$session = $this->getRequest()->getSession();
$json = $session->get('json');
$serializer = new Serializer(array(new GetSetMethodNormalizer()), array('json' => new JsonEncoder()));
$coupon = $serializer->decode($json, 'json');

$coupon is a normalized array of the serialized data. Then assuming the class you want this data to be instantiated of is called Coupon, you need to denormalize it:

$coupon = $serializer->denormalize($coupon, 'Coupon');

Mind the namespaces, the classname Coupon might not be correct.

answered Sep 20, 2011 at 10:31

hakre

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2 Comments

michael Over a year ago

hmm.. thats close, but there are entities within the Coupon class. These are set using setCity($city City) for example, and instead of passing in the object it trys to pass in the Array with all of cities attributes (id, cityname, state etc). I'm thinking I'll have to parse the entire thing by hand ;/

hakre Over a year ago

Well I won't go that far, but just denormalize the sub-values before you denomarlize the main array. That should do it.

Stephan · Accepted Answer · 2012-10-11 08:53:04Z

1

I would recommend using the JMSSerializerBundle.

Its serializer is way more advanced than the serializer that the one from the Serializer Component.

edited Oct 11, 2012 at 8:53

Stephan

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answered Jul 26, 2012 at 14:37

Matthias Noback

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1 Comment

Stephan Over a year ago

Could you please list the differences and or pros/cons between the components in your answer ? It's difficult to appreciate its quality with only way more advanced.

j0k · Accepted Answer · 2012-07-26 14:43:50Z

0

Another interesting option with JSON class hinting.

edited Jul 26, 2012 at 14:43

j0k

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answered Jan 16, 2012 at 14:02

webda2l

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