I want to exit from a loop when both i and j have the value 6, but it exits when one of them has the value 6.
int i,j,k;
i=k=0;
j=1;
Random num = new Random();
Console.WriteLine("Please Press any Key to Roll");
while((i!=6)&&(j!=6))
{
Console.ReadKey();
i= num.Next(0,7);
j= num.Next(0,7);
Console.WriteLine("1st Rolled Number is: "+ i);
Console.WriteLine("2st Rolled Number is: "+ j);
k++;
}
Console.WriteLine("Your have achieved it in "+ k + " Atempts");
To exit the loop when both i and j have the value 6, you can change the condition in the while loop to
Change too
while ((i != 6) || (j != 6))
This will exit the loop when either i or j. To exit the loop when both i and j have the value 6,
while (!(i == 6 && j == 6))
This will exit the loop when both i and j have the value 6.
In other words, the loop should continue if either i isn't 6 or j isn't 6 - this is a logical or (||) condition, not a logical and (&&) condition:
while ((i != 6) || (j != 6))
an alternative approach can be
while(true)
{
Console.ReadKey();
i = num.Next(0, 7);
j = num.Next(0, 7);
Console.WriteLine("1st Rolled Number is: " + i);
Console.WriteLine("2st Rolled Number is: " + j);
k++;
if (i == 6 && j == 6) break;
}
Console.WriteLine("You have achieved it in " + k + " attempts");